我正在尝试创建一个具有同步性的程序,但是遇到一个问题,我正在创建一组大小为3的信号量。
尝试执行semctl将信号量的值设置为0时,我得到的数值结果超出范围错误。
这是它从以下位置生成错误的代码:
int main(int argc, char *argv[]){
char *fileName = argv[0];
int value = 0;
int semID, memID;
int status = 0;
int pipe1[2], pipe2[2], pipe3[2], pipe4[2], pipe5[2], pipe6[2], pipe7[2], pipe8[2], pipe9[2];
pid_t PID1, PID2, PID3, PID4, PID5, PID6, PID7, PID8, PID9, waitPID;
char *buffer;
int check = 0;
struct sembuf operations[1];
int argCount = 4;
int size = 20;
char **args = (char **) malloc( (argCount) * (sizeof (char *) ));
args[0] = (char *) malloc( (size) * (sizeof (char ) ));
args[1] = (char *) malloc( (size) * (sizeof (char ) ));
args[2] = (char *) malloc( (size) * (sizeof (char ) ));
args[3] = (char *) malloc( (strlen(fileName)) * (sizeof (char ) ));
union semun {
int value;
struct semid_ds *buffer;
ushort *array;
} arg;
char *fileNameOutput = (char *) "output.txt";
FILE *fPTR = fopen(fileNameOutput, "w");
/*
* Create a set of 3 semaphores to control the correct synchronization
* then set all semaphores to value of 0
*/
semID = semget(key, 3, 0666 | IPC_CREAT);
if(semID < 0){
fprintf(stderr, "Semaphore not created\n" );
exit(0);
}
printf("value of semaphore after creation: %d, %d , %d\n", semctl(semID, 0, SETVAL, arg), semctl(semID, 1, SETVAL, arg), semctl(semID, 2, SETVAL, arg) );
if(semctl(semID, 0, SETVAL, arg) < 0){
printf( "%s\n", strerror(errno) );
fprintf(stderr, "was unable to set value of sempahore 0\n" );
exit(0);
}
if(semctl(semID, 1, SETVAL, arg) < 0){
fprintf(stderr, "was unable to set value of sempahore 1\n" );
exit(0);
}
if(semctl(semID, 2, SETVAL, arg) < 0){
fprintf(stderr, "was unable to set value of sempahore 2\n" );
exit(0);
}
答案 0 :(得分:0)
arg
成员尚未初始化或未分配任何值。因此,它们包含随机/垃圾值。需要这样设置:
arg.value = MY_SEM_VALUE;
int res = semctl(semID, 0, SETVAL, arg);