将短划线下拉选择传递给变量

时间:2019-12-09 17:39:13

标签: python api flask plotly-dash

我在获取参数以继承仪表板中用户下拉选项时遇到麻烦。

下面是我的代码的三个部分。我不认为问题出在布局/绘图部分,因为如果删除Dropdown对象并显式分配boro变量(即,取消注释第1部分的第一行),便能够填充图形。 。此外,如果我没有绘制图形就进行测试,而只是尝试打印变量值,则使用下拉菜单时它仍然显示空白。

有人可以提供一些帮助吗?我正在处理Plotly Dash教程(https://dash.plot.ly/dash-core-components/dropdown)中给出的示例,但是不确定我是否正确翻译了它们。

第1部分:从API中提取数据

#boro = 'Bronx'
def getHealth(boro):
    health_url = ('https://data.cityofnewyork.us/resource/nwxe-4ae8.json?' +\
            '$select=health,count(tree_id)' +\
            '&$where=boroname=\'' + boro + '\'' +\
            '&$group=health').replace(' ', '%20')
    health_trees = pd.read_json(health_url)

def getStew(boro):
    stew_url = ('https://data.cityofnewyork.us/resource/nwxe-4ae8.json?' +\
            '$select=steward,health,count(tree_id)' +\
            '&$where=boroname=\'' + boro + '\'' +\
            '&$group=steward,health').replace(' ', '%20')
    stew_trees = pd.read_json(stew_url)

第2部分:设置布局,创建图形

app.layout = html.Div(children=[
    html.H1(children='Trees Overview'),

    html.Div(children='''
        HEALTH QUALITY
    '''),
    dcc.Dropdown(
        id='dropdown',
        options=[{'label': i, 'value': i} for i in trees.boroname.unique()],
        value='Bronx',
        clearable=False
    ),
    html.Div(id='table-container'),
])

def generateGraphs(df1,df2,df3):
    return dcc.Graph(
        id='graph1',
        figure={
            'data': [
                go.Pie(labels=df1['health'],values=df1['count_tree_id']),
            ],
            'layout': {
                'title': 'Count By Species'
            }
        }
    ),

    dcc.Graph(
        id='graph2',
        figure={
            'data': [
                go.Bar(x=df2[df2['steward']==i]['health']
                       ,y=df2[df2['steward']==i]['count_tree_id']
                       ,name=i
                       ,marker=go.bar.Marker(
                    color='rgb(26, 118, 255)'
                ))
                for i in df3['steward'].unique()
            ]
        }
    )

第3部分:我认为这是问题所在。我是否正确使用@app.callback函数?我是否在定义retHealth()并正确调用generateGraphs()

@app.callback(
    dash.dependencies.Output('table-container', 'children'),
    [dash.dependencies.Input('dropdown', 'value')])
def retHealth(value):
    health=getHealth(value)
    stew=getStew(value)
    return generateGraphs(health,stew,trees)

1 个答案:

答案 0 :(得分:1)

您的回电没问题。

问题是您没有在 getHealthgetStew 内返回任何内容。这意味着 None 被隐式返回。

因此更改这些函数以返回用于绘制图形的 DataFames:

def getHealth(boro):
    health_url = (
        "https://data.cityofnewyork.us/resource/nwxe-4ae8.json?"
        + "$select=health,count(tree_id)"
        + "&$where=boroname='"
        + boro
        + "'"
        + "&$group=health"
    ).replace(" ", "%20")
    return pd.read_json(health_url)


def getStew(boro):
    stew_url = (
        "https://data.cityofnewyork.us/resource/nwxe-4ae8.json?"
        + "$select=steward,health,count(tree_id)"
        + "&$where=boroname='"
        + boro
        + "'"
        + "&$group=steward,health"
    ).replace(" ", "%20")
    return pd.read_json(stew_url)