Question

我有一个查询，该查询使所有用户都具有报表管理器。我想通过报告经理电子邮件ID将用户ID分组为列表。

SELECT q.USER_ID, q.REPORTS_TO, e.EMAIL
  FROM (SELECT a.USER_ID, a.REPORTS_TO, a.EMAIL
          FROM PortalX.PTX_USERS a
               LEFT OUTER JOIN PortalX.PTX_LDAP_USERS b
                  ON a.USER_ID = b.OWN_ID
         WHERE b.OWN_ID IS NULL) q
       INNER JOIN PortalX.PTX_USERS e ON q.REPORTS_TO = e.USER_ID;

我对编写oracle查询不是很熟悉。任何帮助表示赞赏。

编辑：

在@Barbaros的帮助下，她是最终查询，该查询将用户聚合为用逗号分隔的值的列表。

SELECT a.REPORTS_TO, a.EMAIL, 
       LISTAGG(a.USER_ID,',') WITHIN GROUP (ORDER BY a.USER_ID) as USERS
  FROM PortalX.PTX_USERS a
  LEFT JOIN PortalX.PTX_LDAP_USERS b
    ON a.USER_ID = b.OWN_ID
   AND a.REPORTS_TO = a.USER_ID
 WHERE b.OWN_ID IS NULL
 GROUP BY a.REPORTS_TO, a.EMAIL;

Answer 1

您可以使用这样的查询

SELECT a.REPORTS_TO, a.EMAIL, 
       LISTAGG(a.USER_ID) WITHIN GROUP (ORDER BY a.USER_ID) as USERS
  FROM PortalX.PTX_USERS a
  LEFT JOIN PortalX.PTX_LDAP_USERS b
    ON a.USER_ID = b.OWN_ID
   AND a.REPORTS_TO = a.USER_ID
 WHERE b.OWN_ID IS NULL
 GROUP BY a.REPORTS_TO, a.EMAIL;

包含listagg()函数

Answer 2

似乎您需要一个LISTAGG函数-

SELECT LISTAGG(q.USER_ID), q.REPORTS_TO, e.EMAIL
FROM (SELECT a.USER_ID, a.REPORTS_TO, a.EMAIL
      FROM PortalX.PTX_USERS a
      LEFT OUTER JOIN PortalX.PTX_LDAP_USERS b
                      ON a.USER_ID = b.OWN_ID
      WHERE b.OWN_ID IS NULL) q
      INNER JOIN PortalX.PTX_USERS e ON q.REPORTS_TO = e.USER_ID
GROUP BY q.REPORTS_TO, e.EMAIL;

如何在Oracle中使用分组依据列出汇总值

2 个答案: