Question

在Oracle中，我遇到了从我正在使用的表中获取聚合值的问题。我在下面提供样品。但从汇总的角度来看，我甚至不确定从哪里开始。我想我需要使用case和having的组合，但我不确定如何表达它。

我的表格如下：

    Record#  Value
    111111   KA
    111111   RA
    111111   HA
    111112   KA
    111113   RA
    111114   HA
    111114   RA

期望的结果。我想得到的是获得记录的计数：

    # Records only have KA only.
    # Records only have RA only.
    # Records only have RH only.
    # Records only have HA only.  
    # Records only have KA and RA.
    # Records only have KA and RH.
    # Records only have KA, RA and RH.
    and etc.

我的数量和价值有限，但我在那里有超过1,000,000条记录，我需要了解这些记录的构成。

我会为它创造一个小提琴，但它似乎目前已被打破。

 create table myTable(record  varchar2(100), value varchar2(100));
 insert into myTable(record ,value) values(111111,'KA');
 insert into myTable(record ,value) values(111111,'RA');
 insert into myTable(record ,value) values(111111,'HA');
 insert into myTable(record ,value) values(111112,'KA');
 insert into myTable(record ,value) values(111113,'RA');
 insert into myTable(record ,value) values(111114,'HA');
 insert into myTable(record ,value) values(111114,'RA');

编辑*使用@ Gordon-Linoff建议的内容后，

 select valuelist, count(*) as cnt
 from (select record, listagg(value, ',') within group (order by value) as valuelist, count(*) as cnt
       from mytable
       group by record
      ) r
 group by valuelist
 order by cnt, valuelist;

我得到的混合结果看起来更像是

 KA 2
 RA 3
 HA 2

而不是

 KA, RA, HA 2
 KA 1
 RA 1
 HA, RA 1

Answer 1

您可以通过使用listagg()组合字段然后按结果聚合来执行此操作：

select valuelist, count(*) as cnt
from (select record, listagg(value, ',') within group (order by value) as valuelist, count(*) as cnt
      from mytable
      group by record
     ) r
group by valuelist
order by cnt, valuelist;

使用Group By和ListAgg获取聚合信息

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