Question

我有一个包含集合类型的表。我想从表中SELECT和GROUP BY一些列。我希望每个组的结果都包含一个集合，该集合包含组中所有单个集合的不同联合。

例如，

CREATE OR REPLACE TYPE my_varchar2_list AS TABLE OF VARCHAR2 (80);

WITH test_data (id, a_list) AS
       (SELECT 1,
               NEW my_varchar2_list ('A', 'B', 'C')
        FROM   DUAL
        UNION ALL
        SELECT 1,
               NEW my_varchar2_list ('C', 'D', 'E')
        FROM   DUAL)
SELECT id,
       ... some magic syntax here...
FROM   test_data
GROUP BY id

Desired results:

1,  ('A','B','C','D','E')

我在答案中寻找的内容

我只是在寻找可以插入＆＃34;魔法语法的表达式来到这里＆＃34;上面的占位符。我知道我可以通过将TABLE(a_list)加入主表或以其他方式重构我的查询（或者当然，使用PL / SQL）来完成聚合。请不要在这些方面提供答案：他们不回答我的问题。

Answer 1

从my answer改编为另一个问题。

Oracle安装程序：

CREATE OR REPLACE TYPE VARCHAR2s_Table IS TABLE OF VARCHAR2(100);
/

创建用户定义的聚合类型：

CREATE OR REPLACE TYPE Varchar2sTableUnion AS OBJECT(
  list VARCHAR2s_Table,

  STATIC FUNCTION ODCIAggregateInitialize(
    ctx         IN OUT Varchar2sTableUnion
  ) RETURN NUMBER,

  MEMBER FUNCTION ODCIAggregateIterate(
    self        IN OUT Varchar2sTableUnion,
    value       IN     VARCHAR2s_Table
  ) RETURN NUMBER,

  MEMBER FUNCTION ODCIAggregateTerminate(
    self        IN OUT Varchar2sTableUnion,
    returnValue    OUT VARCHAR2s_Table,
    flags       IN     NUMBER
  ) RETURN NUMBER,

  MEMBER FUNCTION ODCIAggregateMerge(
    self        IN OUT Varchar2sTableUnion,
    ctx         IN OUT Varchar2sTableUnion
  ) RETURN NUMBER
);
/

CREATE OR REPLACE TYPE BODY Varchar2sTableUnion
IS
  STATIC FUNCTION ODCIAggregateInitialize(
    ctx         IN OUT Varchar2sTableUnion
  ) RETURN NUMBER
  IS
  BEGIN
    ctx := Varchar2sTableUnion( NULL );
    RETURN ODCIConst.SUCCESS;
  END;

  MEMBER FUNCTION ODCIAggregateIterate(
    self        IN OUT Varchar2sTableUnion,
    value       IN     VARCHAR2s_Table
  ) RETURN NUMBER
  IS
  BEGIN
    IF value IS NULL THEN
      NULL;
    ELSIF self.list IS NULL THEN
      self.list := value;
    ELSE
      self.list := self.list MULTISET UNION DISTINCT value;
    END IF;
    RETURN ODCIConst.SUCCESS;
  END;

  MEMBER FUNCTION ODCIAggregateTerminate(
    self        IN OUT Varchar2sTableUnion,
    returnValue    OUT VARCHAR2s_Table,
    flags       IN     NUMBER
  ) RETURN NUMBER
  IS
  BEGIN
    returnValue := self.list;
    RETURN ODCIConst.SUCCESS;
  END;

  MEMBER FUNCTION ODCIAggregateMerge(
    self        IN OUT Varchar2sTableUnion,
    ctx         IN OUT Varchar2sTableUnion
  ) RETURN NUMBER
  IS
  BEGIN
    IF self.list IS NULL THEN
      self.list := ctx.list;
    ELSIF ctx.list IS NULL THEN
      NULL;
    ELSE
      self.list := self.list MULTISET UNION DISTINCT ctx.list;
    END IF;
    RETURN ODCIConst.SUCCESS;
  END;
END;
/

创建用户定义的聚合函数：

CREATE FUNCTION MULTISET_UNION( list VARCHAR2s_Table )
RETURN VARCHAR2s_Table
PARALLEL_ENABLE AGGREGATE USING Varchar2sTableUnion;
/

<强>查询：

然后您可以使用它在查询中执行聚合：

WITH test_data (id, a_list) AS
       (SELECT 1,
               varchar2s_table ('A', 'B', 'C')
        FROM   DUAL
        UNION ALL
        SELECT 1,
               varchar2s_table ('C', 'D', 'E')
        FROM   DUAL)
SELECT id,
       MULTISET_UNION( a_list )
FROM   test_data
GROUP BY id

<强>输出：

ID MULTISET_UNION(A_LIST)
-- -------------------------------------------
 1 SCHEMA.VARCHAR2S_TABLE('A','B','C','D','E')

在SQL GROUP BY中聚合集合中的不同值

我在答案中寻找的内容

1 个答案: