Question

对于图像分割问题，我需要编写一个自定义损失函数。我低于上述错误。

代码库：https://www.tensorflow.org/tutorials/images/segmentation

最后一层： Conv2DTrans（128,128,2）[请注意，在我的情况下，它只有2个值]

       def call(self, y_true, y_pred):
              ytrue = ytrue.numpy()
              .....

错误：

AttributeError: 'Tensor' object has no attribute 'numpy'

我尝试了py_function和numpy_function但都返回相同的错误还有

      with tf.compat.v1.Session() as sess:
        for i,j in enumerate(sess.run(y_true),sess.run(y_pred)):

Current Model Layers:


Layer (type)                    Output Shape         Param #     Connected to                     
==================================================================================================
input_82 (InputLayer)           [(None, 128, 128, 3) 0                                            
__________________________________________________________________________________________________
model_80 (Model)                [(None, 64, 64, 96), 1841984     input_82[0][0]                   
__________________________________________________________________________________________________
sequential_160 (Sequential)     (None, 8, 8, 512)    1476608     model_80[1][4]                   
__________________________________________________________________________________________________
concatenate_160 (Concatenate)   (None, 8, 8, 1088)   0           sequential_160[0][0]             
                                                                 model_80[1][3]                   
__________________________________________________________________________________________________
sequential_161 (Sequential)     (None, 16, 16, 256)  2507776     concatenate_160[0][0]            
__________________________________________________________________________________________________
concatenate_161 (Concatenate)   (None, 16, 16, 448)  0           sequential_161[0][0]             
                                                                 model_80[1][2]                   
__________________________________________________________________________________________________
sequential_162 (Sequential)     (None, 32, 32, 128)  516608      concatenate_161[0][0]            
__________________________________________________________________________________________________
concatenate_162 (Concatenate)   (None, 32, 32, 272)  0           sequential_162[0][0]             
                                                                 model_80[1][1]                   
__________________________________________________________________________________________________
sequential_163 (Sequential)     (None, 64, 64, 64)   156928      concatenate_162[0][0]            
__________________________________________________________________________________________________
concatenate_163 (Concatenate)   (None, 64, 64, 160)  0           sequential_163[0][0]             
                                                                 model_80[1][0]                   
__________________________________________________________________________________________________
conv2d_transpose_204 (Conv2DTra (None, 128, 128, 2)  2882        concatenate_163[0][0]            
==================================================================================================

我需要一个numpy数组，以便仅将更多焦点放在1而不是0上。现在，度量标准和准确性被大量的零所淹没。

def tumor_loss(y_true,y_pred):
  y_true = y_true.reshape((SHAPE,SHAPE))
  y_pred = y_pred.reshape((SHAPE,SHAPE))

  y_true_ind = np.where(y_true ==1)[1]
  y_pred_ind = np.where(y_pred==1)[1]

  if np.array_equal(y_true_ind,y_pred_ind):
    return 0

  if y_true_ind.shape[0] > y_pred_ind.shape[0]:
    return y_true_ind.shape[0] - np.setdiff1d(y_true_ind,y_pred_ind).shape[0]
  else:
    return y_true_ind.shape[0] - np.setdiff1d(y_pred_ind,y_true_ind).shape[0]

Answer 1

如果您在tf版本> = 2.0上运行，请尝试使用

model.compile(loss=custom_loss, optimizer='adam', run_eagerly=True)

如果您正在使用Keras api。

TF2.0中的自定义损失函数

1 个答案: