Question

我需要删除包含NA的行，但前提是它们仅在前导（后移）即在变量之前出现任何数据。这非常类似于： How to find (not replace) leading NAs, gaps, and final NAs in data.table columns by category 和： How delete leading and trailing rows by condition in R?

但是，我需要按照变量“ ID”进行分组。我将在后面的步骤中估算NA之间的数据。

对尾随的NA也应如此。

初始data.frame看起来像这样：

df1<-data.frame(ID=(rep(c("C1001","C1008","C1009","C1012"),each=17)),
  Year=(rep(c(1996:2012),4)),x1=(floor(runif(68,20,75))),x2= 
  (floor(runif(68,1,100))))

#Introduce leading / tailing NAs

df1[1:5,3]<-NA
df1[18:23,4]<-NA
df1[35:42,4]<-NA
df1[49:51,3]<-NA
df1[66:68,3]<-NA


#introduce "gap"- NAs
set.seed(123)
df1$x1[rbinom(68,1,0.1)==1]<-NA
df1$x2[rbinom(68,1,0.1)==1]<-NA

输出相当长。这是为了在“空白” NA和“前导/尾随” NA之间进行适当的区分

head(df1,10)

      ID Year x1 x2
1  C1001 1996 NA 40
2  C1001 1997 NA 88
3  C1001 1998 NA 37
4  C1001 1999 NA 29
5  C1001 2000 NA 17
6  C1001 2001 42 18
7  C1001 2002 20 48
8  C1001 2003 30 26
9  C1001 2004 66 22
10 C1001 2005 32 67

按ID组，输出应除去开头的NA（请参阅上面的行1：5）。或以下示例中的18:23行：

df1[18:28,]

      ID Year x1 x2
18 C1008 1996 33 NA
19 C1008 1997 26 NA
20 C1008 1998 NA NA
21 C1008 1999 51 NA
22 C1008 2000 31 NA
23 C1008 2001 44 NA
24 C1008 2002 NA 56
25 C1008 2003 47 70
26 C1008 2004 39 91
27 C1008 2005 55 62
28 C1008 2006 40 43

最终输出应如下所示（当然取决于所插入的随机NA！）：

      ID Year x1 x2
6  C1001 2001 42 18
7  C1001 2002 20 48
8  C1001 2003 30 26
9  C1001 2004 66 22
10 C1001 2005 32 67
11 C1001 2006 NA  5
12 C1001 2007 24 70
13 C1001 2008 33 35
14 C1001 2009 60 41
15 C1001 2010 66 82
16 C1001 2011 47 91
17 C1001 2012 41 28
24 C1008 2002 NA 56
25 C1008 2003 47 70
26 C1008 2004 39 91
27 C1008 2005 55 62
28 C1008 2006 40 43
29 C1008 2007 39 54
30 C1008 2008 49  6
31 C1008 2009 NA 26
32 C1008 2010 NA 40
33 C1008 2011 42 20
34 C1008 2012 34 83
44 C1009 2005 51 96
45 C1009 2006 66 96
46 C1009 2007 37 NA
47 C1009 2008 58 26
48 C1009 2009 34 22
52 C1012 1996 51 78
53 C1012 1997 70 17
54 C1012 1998 69 41
55 C1012 1999 35 47
56 C1012 2000 37 86
57 C1012 2001 74 92
58 C1012 2002 54 NA
59 C1012 2003 71 67
60 C1012 2004 45 95
61 C1012 2005 42 52
62 C1012 2006 56 58
63 C1012 2007 28 34
64 C1012 2008 51 35
65 C1012 2009 33  2

谢谢你！

Answer 1

这是一个data.table解决方案，它依靠rleid仅删除主要的NA：

library(data.table)
dt <- as.data.table(df1)

dt[,
   .SD[!(rleid(x1) %in% c(1, max(rleid(x1))) & is.na(x1)) &
         !(rleid(x2) %in% c(1, max(rleid(x2))) & is.na(x2))],
   by = ID
   ]

要自动对多个列进行操作（假设它们都以x开头），您可以这样做：

dt[dt[, Reduce('&',
               lapply(.SD, function(x) !(rleid(x) %in% c(1, max(rleid(x1))) & is.na(x)))),
      by = ID,
      .SDcols = grep('x', names(dt))]$V1
   ]
# or using .SD as before

dt[,
   .SD[Reduce('&', lapply(.SD, function(x) !(rleid(x) %in% c(1, max(rleid(x1))) & is.na(x)))),
       .SDcols = grep('x', names(dt))],
   by = ID
   ]

或与dplyr相同的想法：

library(dplyr)
library(data.table)

df1%>%
  group_by(ID)%>%
  filter_at(vars(starts_with('x')), all_vars(!(is.na(.) & rleid(.) %in% c(1, max(rleid(.))))))

结果显示42行：

# A tibble: 42 x 4
# Groups:   ID [4]
   ID     Year    x1    x2
   <fct> <int> <dbl> <dbl>
 1 C1001  2001    25    54
 2 C1001  2002    28    50
 3 C1001  2003    35    94
 4 C1001  2004    52    34
 5 C1001  2005    60    47
 6 C1001  2006    NA     9
 7 C1001  2007    67    86
 8 C1001  2008    58    40
 9 C1001  2009    61    73
10 C1001  2010    28    18
# ... with 32 more rows

Answer 2

这是一种使用var toReturn = new Scintilla(); toReturn.Dock = DockStyle.Fill; toReturn.HScrollBar = true; toReturn.VScrollBar = true; if (lineNumbers) toReturn.Margins[0].Width = 40; //allows display of line numbers else foreach (var margin in toReturn.Margins) margin.Width = 0; toReturn.ClearCmdKey(Keys.Control | Keys.S); //prevent Ctrl+S displaying ascii code toReturn.ClearCmdKey(Keys.Control | Keys.R); //prevent Ctrl+R displaying ascii code toReturn.ClearCmdKey(Keys.Control | Keys.W); //prevent Ctrl+W displaying ascii code的方法，该方法用filter_at()来标识前导NA值，并以相同的思想但后向矢量来标识尾随值。

cumsum()

Answer 3

使用data.table的另一个选项：

f4 <- function(DT) {
    setindex(DT, ID)
    DT[, rn := .I]
    uid <- DT[,.(ID=unique(ID), V=TRUE)]
    rows <- rbindlist(lapply(cols, function(x) {
        merge(
            DT[, V := !is.na(get(x))][uid, on=c("ID", "V"), mult="first", .(ID, S=rn)],
            DT[uid, on=c("ID", "V"), mult="last", .(ID, E=rn)],
            by="ID")
    }))[, .(S=max(S), E=min(E)) , ID]
    DT[rows, on=.(ID, rn>=S, rn<=E), .SD]
}
f4(df1)

输出：

       ID Year V1 V2 rn     V
 1: C1001 2001 45 70  6  TRUE
 2: C1001 2002 74 78  6  TRUE
 3: C1001 2003 48  9  6  TRUE
 4: C1001 2004 27 32  6  TRUE
 5: C1001 2005 39  3  6  TRUE
 6: C1001 2006 NA 89  6  TRUE
 7: C1001 2007 22  2  6  TRUE
 8: C1001 2008 56 12  6  TRUE
 9: C1001 2009 29 34  6  TRUE
10: C1001 2010 30 53  6  TRUE
11: C1001 2011 61 46  6  TRUE
12: C1001 2012 23 42  6  TRUE
13: C1008 2002 NA 95 24  TRUE
14: C1008 2003 71 64 24  TRUE
15: C1008 2004 41 92 24  TRUE
16: C1008 2005 45 28 24  TRUE
17: C1008 2006 74 59 24  TRUE
18: C1008 2007 45 16 24  TRUE
19: C1008 2008 57 64 24  TRUE
20: C1008 2009 NA 35 24  TRUE
21: C1008 2010 NA  2 24  TRUE
22: C1008 2011 32 27 24  TRUE
23: C1008 2012 69 41 24  TRUE
24: C1009 2005 30 24 44  TRUE
25: C1009 2006 43 49 44  TRUE
26: C1009 2007 50 NA 44 FALSE
27: C1009 2008 28 72 44  TRUE
28: C1009 2009 43 20 44  TRUE
29: C1012 1996 36 73 52  TRUE
30: C1012 1997 52  4 52  TRUE
31: C1012 1998 67 14 52  TRUE
32: C1012 1999 39 59 52  TRUE
33: C1012 2000 56 12 52  TRUE
34: C1012 2001 25 92 52  TRUE
35: C1012 2002 26 NA 52 FALSE
36: C1012 2003 73 11 52  TRUE
37: C1012 2004 39 50 52  TRUE
38: C1012 2005 65 89 52  TRUE
39: C1012 2006 70 21 52  TRUE
40: C1012 2007 54 86 52  TRUE
41: C1012 2008 37 70 52  TRUE
42: C1012 2009 66 22 52  TRUE
       ID Year V1 V2 rn     V

数据：

library(data.table)
df1 <- data.frame(ID=(rep(c("C1001","C1008","C1009","C1012"),each=17)),
    Year=(rep(c(1996:2012),4)), V1=(floor(runif(68,20,75))), V2=
        (floor(runif(68,1,100))))
df1[1:5,3]<-NA
df1[18:23,4]<-NA
df1[35:42,4]<-NA
df1[49:51,3]<-NA
df1[66:68,3]<-NA
set.seed(123)
df1$V1[rbinom(68,1,0.1)==1]<-NA
df1$V2[rbinom(68,1,0.1)==1]<-NA
setDT(df1)[, rn := .I]
cols <- paste0("V", 1:5)

具有大量行和大量组的数据的计时代码：

set.seed(0L)
if ((BIGDATA <- TRUE)) {
    nr <- 1e7
    nc <- 5
    nid <- 1e5
    dat <- data.table(ID=sample(nid, nr, TRUE),
        as.data.table(matrix(sample(c(1, NA), nr*nc, TRUE), ncol=nc)),
        key="ID")
    cols <- paste0("V", 1:5)
} else {
    df1 <- data.frame(ID=(rep(c("C1001","C1008","C1009","C1012"),each=17)),
        Year=(rep(c(1996:2012),4)), V1=(floor(runif(68,20,75))), V2=
            (floor(runif(68,1,100))))
    df1[1:5,3]<-NA
    df1[18:23,4]<-NA
    df1[35:42,4]<-NA
    df1[49:51,3]<-NA
    df1[66:68,3]<-NA
    set.seed(123)
    df1$V1[rbinom(68,1,0.1)==1]<-NA
    df1$V2[rbinom(68,1,0.1)==1]<-NA
    dat <- setDT(df1)[, rn := .I]
    cols <- paste0("V", 1:2)
}

DT0 <- copy(dat)
DT1 <- copy(dat)
DT2 <- copy(dat)
DT3 <- copy(dat)
DT4 <- copy(dat)

f0 <- function(DT) {
    DT[DT[, Reduce('&',
        lapply(.SD, function(x) {
            r <- rleid(x)
            !(r %in% c(1, max(r)) & is.na(x))
        })),
        ID,
        .SDcols=cols]$V1]
}

f1 <- function(DT) {
    DT[, c("rn", "rid") := .(.I, rowid(ID))][.N:1L, rev_rid := rowid(ID)]

    for (x in cols) {
        idx <- DT[is.na(get(x)) & ID %in% DT[is.na(get(x)) & (rid==1L | rev_rid==1L), ID],
            if (rid[1L]==1L || rev_rid[.N]==1L) rn,
            cumsum(c(0L, diff(rn) > 1L))]$V1
        DT <- DT[!rn %in% idx]
    }

    DT
}

f2 <- function(DT) {
    DT[, c("rn", "rid") := .(.I, rowid(ID))][.N:1L, rev_rid := rowid(ID)]

    for (x in cols) {
        DT <- DT[!rn %in% DT[is.na(get(x)),
            if (rid[1L]==1L || rev_rid[.N]==1L) rn,
            cumsum(c(0L, diff(rn) > 1L))]$V1]
    }

    DT
}

f3 <- function(DT) {
    DT[, rn := .I]
    rows <- DT[, transpose(lapply(.SD, function(x) c(rn[match(TRUE, !is.na(x))],
            rev(rn)[match(TRUE, !is.na(rev(x)))]))),
        ID, .SDcols=cols][, .(S=max(V1), E=min(V2)) , ID]
    DT[rows, on=.(ID, rn>=S, rn<=E), .SD]
}

f4 <- function(DT) {
    setindex(DT, ID)
    DT[, rn := .I]
    uid <- DT[,.(ID=unique(ID), V=TRUE)]
    rows <- rbindlist(lapply(cols, function(x) {
        merge(
            DT[, V := !is.na(get(x))][uid, on=c("ID", "V"), mult="first", .(ID, S=rn)],
            DT[uid, on=c("ID", "V"), mult="last", .(ID, E=rn)],
            by="ID")
    }))[, .(S=max(S), E=min(E)) , ID]
    DT[rows, on=.(ID, rn>=S, rn<=E), .SD]
}

microbenchmark::microbenchmark(f0(DT0), f1(DT1), f2(DT2), f3(DT3), f4(DT4), times=3L)

时间：

Unit: seconds
    expr       min        lq      mean    median        uq       max neval
 f0(DT0)  8.874985  8.950951  8.993281  9.026917  9.052429  9.077942     3
 f1(DT1) 16.249656 16.337013 16.657910 16.424370 16.862038 17.299706     3
 f2(DT2) 18.225748 18.284212 18.391198 18.342676 18.473922 18.605169     3
 f3(DT3) 10.361079 10.612313 10.698897 10.863548 10.867806 10.872063     3
 f4(DT4)  3.106936  3.137846  3.173174  3.168755  3.206293  3.243830     3

另一种具有相同行数但组数少得多的测试：

set.seed(0L)
nr <- 1e7
nc <- 5
nid <- 1e2
dat <- data.table(ID=sample(nid, nr, TRUE),
    as.data.table(matrix(sample(c(1, NA), nr*nc, TRUE), ncol=nc)),
    key="ID")
cols <- paste0("V", 1:5)
DT0 <- copy(dat)
DT3 <- copy(dat)
microbenchmark::microbenchmark(f0(DT0), f3(DT3), f4(DT4), times=3L)

时间：

Unit: seconds
    expr      min       lq     mean   median       uq      max neval
 f0(DT0) 2.317905 2.331944 2.358256 2.345983 2.378431 2.410880     3
 f3(DT3) 2.108385 2.123889 2.132315 2.139392 2.144280 2.149168     3
 f4(DT4) 2.050805 2.079687 2.101211 2.108569 2.126414 2.144258     3

如何在R中按组删除开头和结尾的NA的行

3 个答案: