Question

我想知道是否可以将文件从Mathematica上传到ifile.it。我已经看过ifile.it的API，但是，我仍然不知道它是如何工作的。此外，我在Mathematica中看到的最接近的例子是“Twittering with Mathematica”，但我不清楚，如何使用该示例中的GET请求。

提前致谢

Answer 1

设置Java HttpClient库。

<< JLink`

client = JavaNew["org.apache.commons.httpclient.HttpClient"]
(*
Out[3]= JLink`Objects`vm1`JavaObject17955866594508801
*)

确定要使用的服务器。

method = JavaNew["org.apache.commons.httpclient.methods.GetMethod", 
  "http://ifile.it/upload:api_fetch_upload_server"]

(*
Out[4]= JLink`Objects`vm1`JavaObject3301364646019073
*)

client@executeMethod[method]  

(*
Out[5]= 200
*)

id = "server_id" /. ImportString[method@getResponseBodyAsString[], "JSON"]

(*
Out[6]= "55"
*)

使用带有FilePart的MultipartRequestEntity，使用POST请求将文件上传到服务器。

method = JavaNew["org.apache.commons.httpclient.methods.PostMethod", 
  "http://s" <> ToString[id] <> ".ifile.it/upload?apikey=" <> apikey]

(*
Out[7]= JLink`Objects`vm1`JavaObject25911718337052673
*)

filename = NotebookFileName[];

file = JavaNew["java.io.File", filename]

(*
Out[9]= JLink`Objects`vm1`JavaObject27844190972936193
*)

part = JavaNew["org.apache.commons.httpclient.methods.multipart.FilePart", 
  file@getName[], file]

(*
Out[10]= JLink`Objects`vm1`JavaObject17546309972000769
*)

part@setContentType["application/vnd.wolfram.mathematica"]

part@setName["Filedata"]

entity = JavaNew[
  "org.apache.commons.httpclient.methods.multipart.MultipartRequestEntity", 
{part}, method@getParams[]]

(*
Out[13]= JLink`Objects`vm1`JavaObject22100383232950273
*)

method@setRequestEntity[entity]

client@executeMethod[method]

(*
Out[15]= 200
*)

ImportString[method@getResponseBodyAsString[], "JSON"]

(*
Out[16]= {"file_key" -> "b8em0dc", 
 "file_md5" -> "acc9b7b3910b1e40188cf26ae3f20b80", 
 "file_mime" -> "text/plain", "file_name" -> "ifile.it.nb", 
 "file_size" -> "10473", "hash" -> "ca3d886713f64af6e9ffe6c3843d2eec", 
 "status" -> "ok", "url" -> "http://ifile.it/b8em0dc/ifile.it.nb"}
*)

Answer 2

ragfield的回答得到了不是黑客攻击的分数，但你也可以在没有JLink的情况下做到这一点：

UploadFile[url_, filePath_, urlParams___] := With[
  {
    bytes = Import[filePath, "Byte"],
    filename = StringJoin[FileBaseName[filePath], ".", FileExtension[filePath]]
  },
  URLExecute[
    url,
    urlParams,
    "Method" -> "POST",
    "MultipartElements" -> {
      {"file\"; filename=\"" <> filename, "application/octet-stream", bytes}
    },
    "Headers" -> {
      "Accept" -> "application/json; charset=UTF-8",
      "Content-Type" -> "multipart/form-data"
    }
  ]
]

（来自https://mathematica.stackexchange.com/questions/52338/more-complete-mutipartdata-posts-using-urlfetch/97658#97658的交叉答案）

通过Mathematica上传到ifile.it

2 个答案: