我无法将XML转换为python数据框
能否请您帮我将XML解析为python数据框? 我似乎无法正常工作 这是我到达的距离:
import xmltodict
import pandas as pd
import requests
from bs4 import BeautifulSoup
def get_xml():
url="http://energywatch.natgrid.co.uk/EDP-PublicUI/PublicPI/InstantaneousFlowWebService.asmx"
headers = {'content-type': 'application/soap+xml; charset=utf-8'}
body ="""<soap12:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap12="http://www.w3.org/2003/05/soap-envelope">
<soap12:Body>
<GetInstantaneousFlowData xmlns="http://www.NationalGrid.com/EDP/UI/" />
</soap12:Body>
</soap12:Envelope>"""
response = requests.post(url,data=body,headers=headers)
return response.content
response = get_xml()
soup = BeautifulSoup(response, 'lxml')
table_columns = []
for item in soup.find_all(['EDPObjectName'.lower()]):
table_columns.append(item.text)
table_columns=pd.DataFrame(table_columns)
table_rows=[]
for item in soup.find_all(['applicableat']):
table_rows.append(item.text)
df1=pd.DataFrame(table_rows).drop_duplicates()
#df1=pd.to_datetime(df1)
table=[]
for item in soup.find_all(['flowrate']):
table.append(item.text)
df=pd.DataFrame(table)
df_final=pd.DataFrame(df, columns=table_columns, index=df1)
这是我要寻找的结果:
ALDBROUGH AVONMOUTH BACTON BBL …
2019-08-08T13:00:00 0 1.23 5.1 …
2019-08-08T13:02:00 0 1.23 5.1 …
2019-08-08T13:04:00 0 3.23 5.1 …
2019-08-08T13:06:00 0 3.23 5.1 …
2019-08-08T13:08:00 0 3.23 5.23 …
2019-08-08T13:10:00 0 4.23 5.204 …
答案 0 :(得分:0)
此问题与其他xml解析问题非常相似,因为您具有分层数据结构,并且需要对其进行展平。我提出的解决方案将时间戳记,位置和流量变成列,并使每个日志条目都变成一行。我还遵循了简约性原则,即我尝试以某种方式解析xml,以便使扁平化的数据已经具有最容易转换为数据帧的格式。变量“数据”具有字典结构,每一列都有一个键。字典中的值是数据列表,列表中的每个位置指示该条目所属的行:
import pandas as pd
import requests
from bs4 import BeautifulSoup
def get_xml():
url="http://energywatch.natgrid.co.uk/EDP-PublicUI/PublicPI/InstantaneousFlowWebService.asmx"
headers = {'content-type': 'application/soap+xml; charset=utf-8'}
body ="""<soap12:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap12="http://www.w3.org/2003/05/soap-envelope"><soap12:Body><GetInstantaneousFlowData xmlns="http://www.NationalGrid.com/EDP/UI/" /></soap12:Body></soap12:Envelope>"""
response = requests.post(url,data=body,headers=headers)
return response.content
response = get_xml()
soup = BeautifulSoup(response, 'lxml')
data = {'timestamp':[], 'place':[], 'flowrate':[]}
for group in soup.find_all('edpobjectbe'):
place = group.find('edpobjectname').text
for xml in group.find_all('edpenergydatabe'):
data['place'].append(place)
data['timestamp'].append(xml.find('applicableat').text)
data['flowrate'].append(xml.find('flowrate').text)
df = pd.DataFrame(data)
df
请注意,我正在对父元素“ edpenergydatabe”执行find_all(),因此可以确保时间戳适用于与其关联的所有条目。如果您希望行和列的排列方式不同,现在可以使用诸如transpose()之类的熊猫函数来做到这一点。我希望这可以帮助您走上正确的轨道!
答案 1 :(得分:0)
尝试使用:
G
检查它是否适合您!