Question

在我的查询中，我有多个Case When子句，其中一个表中的数字的唯一字符串将指示输出中的唯一字符串/句子值。目前我的问题是我的Case when输出正在处理输出中的总数，但是由于第二个表中不存在第一个表中不存在的多个唯一字符串，因此应该在else语句中求和为一个总数，每个计数都在自己的行上。

我尝试在查询结束时对GROUP BY子句进行ROLLUP，但没有得到所需的预期输出。

这是我现在正在使用的东西：

SELECT 
  F.Identifier, F.Videogame, F.Developer,
CASE WHEN S.String='1581' THEN 'Made by billy'
     WHEN S.String='1903' THEN 'Made by bob'
     WHEN S.String='5849' THEN 'Made by lilly'
     ELSE 'worked on by someone else' END AS Final_Name,
     COUNT(distinct S.User_ID) as Count
FROM 
  table1 as F
JOIN 
  table2 as S
ON
  F.Identifier=S.Identifier
GROUP BY
  F.Identifier, F.Videogame, F.Developer, S.String

这是我当前得到的输出：

abcd | red dead | company1 | worked on by someone else | 1
abcd | red dead | company1 | Made by billy             | 1
defg | halo 3   | company2 | Made by bob               | 1
defg | halo 3   | company2 | worked on by someone else | 1
defg | halo 3   | company2 | worked on by someone else | 1
hijk | fortnite | company3 | Made by lilly             | 1

这是我想要实现的输出：

abcd | red dead | company1 | worked on by someone else | 1
abcd | red dead | company1 | Made by billy             | 1
defg | halo 3   | company2 | Made by bob               | 1
defg | halo 3   | company2 | worked on by someone else | 2
hijk | fortnite | company3 | Made by lilly             | 1

Answer 1

以下是用于BigQuery标准SQL

#standardSQL
SELECT F.Identifier, F.Videogame, F.Developer,
CASE WHEN S.String='1581' THEN 'Made by billy'
     WHEN S.String='1903' THEN 'Made by bob'
     WHEN S.String='5849' THEN 'Made by lilly'
     ELSE 'worked on by someone else' END AS Final_Name,
     COUNT(DISTINCT S.User_ID) AS COUNT
FROM `project.dataset.table1` AS F
JOIN `project.dataset.table2` AS S
ON F.Identifier=S.Identifier
GROUP BY F.Identifier, F.Videogame, F.Developer, Final_Name

如您所见，唯一的解决方法是在最后一行-您需要使用S.String来代替Final_Name

因此，如果将以上内容应用于问题中的采样数据-结果为

Row Identifier  Videogame   Developer   Final_Name                  Count    
1   abcd        red dead    company1    worked on by someone else   1    
2   abcd        red dead    company1    Made by billy               1    
3   defg        halo 3      company2    Made by bob                 1    
4   defg        halo 3      company2    worked on by someone else   2    
5   hijk        fortnite    company3    Made by lilly               1

Answer 2

这就是您需要的。

SELECT 
  F.Identifier, F.Videogame, F.Developer,
CASE WHEN F.String='1581' THEN 'Made by billy'
     WHEN F.String='1903' THEN 'Made by bob'
     WHEN F.String='5849' THEN 'Made by lilly'
     ELSE 'worked on by someone else' END AS Final_Name,
     S.cnt as Count
FROM 
  table1 as F
JOIN 
  (select a.Identifier, b.Developer, count(1) cnt from table2  a
     join table1 b on b.Identifier = a.Identifier
    Group by String, b.Developer) as S
    ON
      F.Identifier=S.Identifier and S.Developer = F.Developer

查询计数其他语句值时的SQL情况

2 个答案: