Question

我需要找到有多少人在60天内提交（fil_dt）纳税申报表，120天内，180天内，提交期限结束日期（fpe）的180天，3年不同（2006年，2007年），2008）

以下声明将给我所有年份我需要每年和每种可能性的计数.. 无论如何，我可以在没有2个查询的情况下做到这一点？

SELECT YEAR(A.FPE) AS "YEAR"
,CASE                                              
  WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 60 THEN '2 ' 
  WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 120 THEN '4 '
  WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 180 THEN '6 '
  WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) > 180 THEN '6+'
 END AS "NBR MTH"                                  
WHERE A.FPE BETWEEN '2006-01-01' AND '2008-12-31'

我需要你的帮助非常感谢

Answer 1

然后写

   SELECT YEAR(A.FPE) AS "YEAR",
       Sum(CASE WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 60 
                  THEN 1 Else 0 End) SixtydayCount,  
       Sum(CASE WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 120 
                  THEN 1 Else 0 End) OneTwentyDayCount,
       Sum(CASE WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 180 
                  THEN 1  Else 0 End) OneEightyDayCount,
       Sum(CASE WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) > 180 
                  THEN 1 Else 0 End)  OverOneEightyCount  
    From Table A
    WHERE A.FPE BETWEEN '2006-01-01' AND '2008-12-31'
    Group By YEAR(A.FPE)

如果您希望120天计数和180天计数仅包括60岁以上且不足120岁的人，那么，

     SELECT YEAR(A.FPE) AS "YEAR",
       Sum(CASE WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 60 
                  THEN 1 Else 0 End) SixtydayCount,  
       Sum(CASE WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) Between 60 And 119 
                  THEN 1 Else 0 End) OneTwentyDayCount,
       Sum(CASE WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) Between 120 And 179 
                  THEN 1  Else 0 End) OneEightyDayCount,
       Sum(CASE WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) >= 180 
                  THEN 1 Else 0 End)  OverOneEightyCount  
    From Table A
    WHERE A.FPE BETWEEN '2006-01-01' AND '2008-12-31'
    Group By YEAR(A.FPE)

Answer 2

SELECT  CASE
        WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 60 THEN '2 ' 
        WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 120 THEN '4 '
        WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 180 THEN '6 '
        WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) > 180 THEN '6+'
        END AS NBR_MTH,
        y,
        COUNT(a.fpe)
FROM    (
        SELECT  2006 AS y
        UNION ALL
        SELECT  2007 AS y
        UNION ALL
        SELECT  2008 AS y
        )
LEFT JOIN
        A
ON      A.FPE >= CAST(CONCAT(y, '-01-01') AS DATETIME)
        AND a.FPE < CAST(CONCAT(y + 1, '-01-01') AS DATETIME)
GROUP BY
        y, mbr_mth

与简单的GROUP BY YEAR()不同，即使是丢失的记录，也会选择0（例如，如果6+中没有2008个记录）

Answer 3

按案例陈述所代表的列分组：

SELECT 
  YEAR(A.FPE) AS "YEAR",
  CASE                                              
    WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 60 THEN '2 ' 
    WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 120 THEN '4 '
    WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 180 THEN '6 '
    WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) > 180 THEN '6+'
  END AS "NBR MTH",
  COUNT(1) AS "TOTAL"
FROM Table
WHERE 
  A.FPE BETWEEN '2006-01-01' AND '2008-12-31'
GROUP BY
  "YEAR",
  "NBR MTH"

此查询将为您提供每个唯一年份/“NBR MTH”组合的每条记录的计数。

Answer 4

实际上，大多数DBMS不允许GROUP BY使用别名，所以它必须是

...
GROUP BY 
  YEAR(A.FPE),
  CASE                                              
    WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 60 THEN '2 ' 
    WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 120 THEN '4 '
    WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 180 THEN '6 '
    WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) > 180 THEN '6+'
  END

带有count和case语句的SQL查询

4 个答案: