从嵌套列表中删除不需要的文本

Question

我希望能够删除列表中不需要的一些单词。

代码：

txt = document.getElementById('title').innerHTML
alert(txt)

输出：

{"Name":"Item Name", "Weight in store":12.3, "Minimum Purchase":12, "Purchase Price":19.99, "Category":"That Thing", "Location":"That Place"},
{"Name":"Other Name", "Weight in store":32.1, "Minimum Purchase":16, "Purchase Price":29.99, "Category":"Other Thing", "Location":"Other Place"}

contour = cnt stopwords = ['array', 'dtype=int32'] for word in list(contour): if word in stopwords: contour.remove(word) print(contour)

如何删除[array([[[21, 21]], [[21, 90]], [[90, 90]], [[90, 21]]], dtype=int32)] 和FutureWarning: elementwise comparison failed; returning scalar instead, but in the future will perform elementwise comparison if word in stopwords:，同时使列表只是两点的列表？

例如：

dtype=int32

Answer 1

使用numpy.ndarray.tolist()：

import numpy as np

l = np.array(
    [np.array([[[21, 21]],

       [[21, 90]],

       [[90, 90]],

       [[90, 21]]], dtype="int32")]
)
l.tolist()

输出：

[[[[21, 21]], [[21, 90]], [[90, 90]], [[90, 21]]]]