Question

我有一个sql查询从表中提取presenter字段。演示者字段位于数组中。所以我这样做：

//convert presenter data from array to string   
    $cleanpresenters = parse_ini_string($data['presenters'],TRUE);
    foreach ($cleanpresenters as $name=>$val1) 
    {
            $name = trim($name);
            $presenters[] = $name;
            $convertedPresenters .= "$name, {$val1['department']}, {$val1['institution']}\n";
    };

将其转换为：

阵（ [Doe，John undefined] =＆gt;排列（ [middle_name] =＆gt; [department] =＆gt;领导力研究 [机构] =＆gt;任何州立大学 [city] =＆gt;顿 [state] =＆gt;哦 [country] =＆gt;美国 [office_phone] =＆gt; 123-456-11258 [cell_phone] =＆gt; [email_address] =＆gt; John.doe@anywhere.edu [网站] =＆gt; ）

[Doe, Jane undefined] => Array
    (
        [middle_name] => 
        [department] => Leadership Studies
        [institution] => Any State University
        [city] => Dayton
        [state] => Oh
        [country] => United States
        [office_phone] => 123-45-7896
        [cell_phone] => 
        [email_address] => John.doe@anywhere.edu
        [website] => 
    )

）

到此：

Doe，John undefined，领导力研究，任何州立大学

Doe，Jane undefined，领导力研究，任何州立大学

输出回显和使用fpdf创建的pdf。我的问题是 - 如何消除（替换为空格）＆＃34; undefined＆＃34;从所有的字符串？我已经尝试过使用preg_replace，但我已经足够了，我无法正常使用它。我是在正确的轨道上还是完全离开基地？谢谢！

Answer 1

要替换php中的字符串，请尝试使用str_replace：

$new_string =  str_replace("undefined"," ","Doe, John undefined, Leadership Studies, Any State University");

Answer 2

您可以使用preg_replace：

来完成此操作

$cleanpresenters = parse_ini_string($data['presenters'],TRUE);
foreach ($cleanpresenters as $name=>$val1) 
{
        $name = trim(preg_replace('/ undefined/i', '', $name));
        $presenters[] = $name;
        $convertedPresenters .= "$name, {$val1['department']}, {$val1['institution']}\n";
};

undefined之前有一个空格，但是如果它不会一直存在，你就可以把它拿出来。

从数组或fpdf中删除不需要的文本

2 个答案: