+---------+-------------+-------------+------------+----------+
| Item | Consumption | %Consumption| %Cumulative| Category |
+---------+-------------+-------------+------------+----------+
| Item 1 | 500 | 28.17 | 28.17 | A |
| Item 2 | 450 | 25.35 | 53.52 | A |
| Item 3 | 350 | 19.72 | 73.24 | A |
| Item 4 | 200 | 11.27 | 84.51 | B |
| Item 5 | 150 | 8.45 | 92.96 | B |
| Item 6 | 100 | 5.63 | 98.59 | B |
| Item 7 | 10 | 0.56 | 99.15 | C |
| Item 8 | 4 | 0.23 | 99.38 | C |
| Item 9 | 2 | 0.11 | 99.49 | C |
| Item 10 | 6 | 0.34 | 99.83 | C |
| Item 11 | 3 | 0.17 | 100.00 | C |
+---------+-------------+-------------+------------+----------+
我希望显示累积列中的ConsumptionPercent
之和。
答案 0 :(得分:3)
以下查询应执行您想要的操作:
SELECT [Item]
,[Consumption]
,[ConsumptionPercent]
,SUM([ConsumptionPercent]) OVER (ORDER BY ([Item]) ROWS UNBOUNDED PRECEDING) AS [Cumulative]
,[Category]
FROM YourTable
答案 1 :(得分:0)
尝试使用窗口函数SUM
select Item,
Consumption,
ConsumptionPercent,
sum(ConsumptionPercent) over (order by id),
Category
from (
select cast(substring(Item, 6, length(item)) as int) id, *
from MyTable
) a