Question

SELECT  b.BranchName ,
        pm.AgreementValue
FROM    dbo.Member AS m
        INNER JOIN dbo.PlanMaster AS pm ON ( m.PlanId = pm.PlanId )
        INNER JOIN dbo.Branch AS b ON ( b.BranchId = m.BranchId )

这是上述查询的结果

BranchName      AgreementValue
------------------------------
abc             60000.00
abc             36000.00
abc             36000.00
xyz             20000.00
xyz             10000.00

现在我希望总共可以获得AgreementValue BranchName ..谢谢你的帮助

Answer 1

GROUP BY b.BranchName SUM就像这样：

SELECT   b.BranchName ,
         SUM(pm.AgreementValue) TotalValue
FROM     dbo.Member AS m
         INNER JOIN dbo.PlanMaster AS pm ON ( m.PlanId = pm.PlanId )
         INNER JOIN dbo.Branch AS b ON ( b.BranchId = m.BranchId )
GROUP BY b.BranchName;

Answer 2

如果您尝试获取每行的总数，请使用sum()的窗口函数：

SELECT  b.BranchName ,
        pm.AgreementValue,
        sum(pm.AgreementValue) over (partition by b.BranchName) as BranchTotal
FROM    dbo.Member AS m
        INNER JOIN dbo.PlanMaster AS pm ON ( m.PlanId = pm.PlanId )
        INNER JOIN dbo.Branch AS b ON ( b.BranchId = m.BranchId )

在SQL Server中获得Total Branch明智

2 个答案: