Question

我试图让所有学者分类。我使用以下查询。

SELECT DISTINCT
    LOGINID,
    ISNULL(SUM(PHD_INTERNAL),0) AS PHD_INTERNAL,
    ISNULL(SUM(MS_INTERNAL),0)  AS MS_INTERNAL,
    ISNULL(SUM(PHD_EXTERNAL),0) AS PHD_EXTERNAL,
    ISNULL(SUM(MS_EXTERNAL),0)  AS MS_EXTERNAL,
    ISNULL((ISNULL(SUM(PHD_INTERNAL), 0)) + (ISNULL(SUM(MS_INTERNAL), 0)) + (ISNULL(SUM(PHD_EXTERNAL), 0)) + (ISNULL(SUM(MS_EXTERNAL),0)),0) AS Total
FROM
    (SELECT DISTINCT
         LOGINID,
         STYPE, CTYPE,
         CASE
             WHEN STYPE = 'Internal' AND CTYPE  = 'Ph.D'
                THEN CNT
         END PHD_INTERNAL,
         CASE
             WHEN STYPE = 'Internal' AND CTYPE  = 'M.S'
                THEN CNT
         END MS_INTERNAL,
         CASE
             WHEN STYPE = 'External' AND CTYPE  = 'Ph.D'
                THEN CNT
         END PHD_ExTERNAL,
         CASE
             WHEN STYPE = 'External' AND CTYPE  = 'M.S'
                THEN CNT
         END MS_EXTERNAL
    FROM
        (SELECT DISTINCT
             LOGINID,
             STYPE, CTYPE,
             COUNT (STYPE) AS CNT
         FROM
             SCHDET
         GROUP BY
             LOGINID, STYPE, CTYPE) T
     ) TT
GROUP BY
    LOGINID

UNION ALL

SELECT
    'Total',
    ISNULL(SUM(IP), 0) AS IP,
    ISNULL(SUM(IMS), 0) AS IMS,
    ISNULL(SUM(EP), 0) AS EP,
    ISNULL(SUM(EMS), 0) AS EMS,
    ISNULL((ISNULL(SUM(IP), 0) + ISNULL(SUM(IMS), 0) + ISNULL(SUM(EP), 0) + ISNULL(SUM(EMS), 0)), 0) AS TOTAL
FROM
    (SELECT
         'TOTAL',
         CASE
             WHEN STYPE = 'Internal' AND CTYPE  = 'Ph.D'
                THEN CNT
         END IP,
         CASE
             WHEN STYPE = 'External' AND CTYPE  = 'Ph.D'
                THEN CNT
         END EP,
         CASE
             WHEN STYPE = 'Internal' AND CTYPE  = 'M.S'
                THEN CNT
         END IMS,
         CASE
             WHEN STYPE = 'External' AND CTYPE  = 'M.S'
                THEN CNT
         END EMS
     FROM
         (SELECT
              STYPE, CTYPE, COUNT (STYPE) CNT
          FROM
              SCHDET
          GROUP BY
              STYPE, CTYPE) B
     ) BB
GROUP BY
    'Total';

但是，我收到了错误：

没有为＆＃39; BB＆＃39;。
的第1列指定列名

请帮帮我。

Answer 1

在视图'BB'中，您需要定义值为'TOTAL'的列的名称。

.....
FROM
  (
    SELECT 'TOTAL' AS TOTAL,
......

Answer 2

始终内部查询应该有一个别名，以便在外部查询中使用它。

select 'Total' as Total,

在SQL Server中按类别计算总数

2 个答案: