Question

我想在sql中明确记录记录。

+----------+-------+----------------------+----------+----------+----------+----------+
| Products | Totel | sellers=COUNT(C2:F2) | seller a | seller b | seller c | seller d |
+----------+-------+----------------------+----------+----------+----------+----------+
| a        |     3 | 23.4                 | 34.2     | null     | 34.2     |          |
| b        |     2 | 23.4                 | null     | 34.2     | null     |          |
| c        |     1 | 23.4                 | null     | null     | null     |          |
| d        |     4 | 23.4                 | 34.2     | 34.2     | 34.2     |          |
+----------+-------+----------------------+----------+----------+----------+----------+

我可以使用this = COUNT（C2：F2）在Excel中执行此操作。在sql中怎么办？

Answer 1

您可以使用：

select sum(
    case when [seller a] is null then 0 else 1 end
    + case when [seller b] is null then 0 else 1 end
    + case when [seller c] is null then 0 else 1 end
    + case when [seller d] is null then 0 else 1 end
)
from your_table

这将给出所有行的总数，因为它似乎不是很明显如何对它进行分组。

Answer 2

这会有效，但需要GROUP BY

Select 
Products,
sum(
      case when SellerA is null then 0 else 1 end
    + case when SellerB is null then 0 else 1 end
    + case when SellerC is null then 0 else 1 end
    + case when SellerD is null then 0 else 1 end
) AS Total_Seller,
SellerA,
SellerB,
SellerC,
SellerD
from MyTable
GROUP BY
Products,
SellerA,
SellerB,
SellerC,
SellerD

或者，你也可以使用它。

Select 
Products,
ISNULL((SellerA/SellerA),0)
+ISNULL((SellerB/SellerB),0)
+ISNULL((SellerC/SellerC),0)
+ISNULL((SellerD/SellerD),0) AS Total_Seller,
SellerA,
SellerB,
SellerC,
SellerD
from MyTable

SQL Fiddle demo

在sql中行明智计数＃

2 个答案: