Question

给出了一个长度为n且旋转了k的数组来执行。我已经尝试过，但是却出错了

shifted = []
size , rotation = [int(size)for size in input().split()]
arr= [int(size) for size in input().split()]
for loop in range(len(arr)):
  indx = (loop+rotation)%len(arr)
  shifted[indx:indx] = arr[loop]

print(shifted)

我收到此错误： shifted [indx：indx] = arr [loop] TypeError：只能分配一个可迭代的

Answer 1

假设向左旋转并输入：

lst = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
k = 3
n = 10

如果不需要就地执行此操作，则可以执行以下操作：

result = lst[k:] + lst[:k] # [3, 4, 5, 6, 7, 8, 9, 0, 1, 2]

deque也是一个选择：

from collections import deque
lst = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
result = deque(lst)
result.rotate(-3) # Rotate 3 to the left
print(list(result))

python中数组旋转的给定数量的移动

1 个答案: