Question

嗨，大家好，当我尝试运行我的程序时，它会弹出一个框，提示语法无效，然后使Elif变成红色

sales_amount = int(input('what is your sales amount to your commission rate 
Example: 5000$ to 2%'))
goal_salary = int(input('what is your goal salary'))
commission_rate = float(input('what is your commissioin rate to your sales 
amount Example: 5000$ to 2%  P.S. please write as decimal'))

final_sales_amount=sales_amount
final_commission_rate=commission_rate
the_number=1
commission=0
sales=0.01

while sales_amount*commission_rate==goal_salary:
    print('your sales amount is', sales)
    print('your commission rate is', commission) 
    break
elif the_number*sales_amount==0.01:
    the_number+1
    commission+commission_rate
else:
    sales=sales+0.01

Answer 1

如果第一个elif与cond不匹配，则使用if。例如：

a = 1
if a ==2:
 print('lol')
elif a == 1:
 print('wow')

在此示例中，输出为wow，但是如果if中的cond为True，则不会检测到elif（或不进行elif代码）。

如果在任何Else中没有cond并且if为True，则使用

elif。例如：

a = 3
if a == 1 or a ==5:
 print('1/5')
elif a == 2 or a == 4:
 print('2/4')
else:
 print('i have nothing')

，输出将为i have nothing，因为a == 1 or a ==5不正确，a ==2 or a == 4也不正确，因此，其他情况，else: print('i have nothing')是命令解决方案的方法

我的Elif陈述出现语法错误

1 个答案: