Question

name=input("Hello person, Whats your name?")
print("Hello", name)
print("Do you want to hear a story?", name)
choice=input("Yes, No?")
if choice==("yes" or "yes " or "Yes" or "Yes "):
    print("Ok", name,", listen up")    
print("There was once an old, old house at the top of a hill Sooooo high it was above the clouds")
choice2=input("What do you want to call the house?")
print("The old,",choice2,"was once owned by an old lady. ")

elif choice==("maybe"):
    print("You found an easter egg, congrats. PS this does nothing")

这段代码有什么问题？它在idle shell语法错误中说。最后一个elif语句不起作用。

Answer 1

这是一个小的缩进问题，if块的打印语句没有缩进，因此elif似乎不合适。请注意，python通过缩进保留track of logical blocks。

name=input("Hello person, Whats your name?")
print("Hello", name)
print("Do you want to hear a story?", name)
choice=input("Yes, No?")
if choice==("yes" or "yes " or "Yes" or "Yes "):
    print("Ok", name,", listen up")    
    print("There was once an old, old house at the top of a hill Sooooo high it was above the clouds")
    choice2=input("What do you want to call the house?")
    print("The old,",choice2,"was once owned by an old lady. ")

elif choice==("maybe"):
    print("You found an easter egg, congrats. PS this does nothing")

正如已经指出的那样，if choice==("yes" or "yes " or "Yes" or "Yes ")是错误的，而是使用if choice.lower().strip() == "yes"或if choice in ("yes", "yes ", "Yes", "Yes ")。

如果这是python 2，input会抛出错误，请改用raw_input。如果像函数一样使用多个语句的print也会抛出错误，因此将它们从print(statement_x, statement_y, statement_z)更改为print statement_x, statement_y, statement_z

Python编程错误，elif语句语法错误简单代码

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