我正在建立一个游戏,让计算机知道你想到的哪种农场动物。他问你猜问你的农场动物的问题。但我收到了一个错误,我不知道如何解决它。
我的代码:
qs_one = raw_input("Do your animal walk on two legs? answar 'yes' or 'no'")
if qs_one == "yes":
qs_two = raw_input("Do your animal have a white skin? answar 'yes' or 'no'")
if qs_two == "yes":
print "Your animal is a goose!"
elif qs_two == "no":
print "Your animal is a chicken!"
else:
print "Error, try again."
elif qs_one == "no":
qs_two = raw_input("Do your animal have horns? answar 'yes' or 'no'")
if qs_two == "yes":
qs_tree = raw_input("Do your animal have stains? answar 'yes' or 'no'")
if qs_tree == "yes":
print "Your animal is a cow!"
elif qs_tree == "no":
qs_four = raw_input("Do your animal have goatee? answar 'yes' or 'no'")
if qs_four == "yes":
print "Your animal is a goat!"
elif qs_four == "no":
print "Your animal is a bull!"
else:
print "Error, try again."
else:
print "Error, try again."
elif qs_two == "no":
qs_tree = raw_input("Do your animal have a pink skin? answar 'yes' or 'no'")
if qs_tree == "yes":
print "Your animal is a pig!"
elif: # <- ERROR HERE
qs_four = raw_input("Can you ride your animal? answar 'yes' or 'no'")
if qs_four == "yes":
print "Your animal is a horse!"
elif qs_four == "no":
qs_five = raw_input("Does your animal have big ears? answar 'yes' or 'no'")
if qs_five == "yes":
"Your animal is a rabbit!"
elif qs_five == "no":
"Your animal is a sheep!"
else:
print "Error, try again."
else:
print "Error, try again."
else:
print "Error, try again."
else:
print "Error, try again."
else:
print "Error, try again."
错误:
Traceback (most recent call last):
File "python", line 30
elif:
^
SyntaxError: invalid syntax``
答案 0 :(得分:4)
你需要有elif
的条件,即
elif condition_is_true:
*do something*
我认为你想要做的是使用elif qs_tree=='no':
。如果“是”,那就是猪,如果“不”,那就是别的,其他每一个答案都应该给出“错误,再试一次” - 消息。