我正在构建SLA KPI。 SLA基于票证类型和优先级,每个都有到期日期。
问题是,我只有一个字段created_at,没有这个到期日,因此我需要进行计算,如上所述,请使用params优先级和类型来定义正确的日期。
但是我真正的问题是,如何在PHP上计算它,考虑到工作日和工作时间,周一至周五,8:00至18:00 例如。
故障单是在2019-06-04 08:00:00
创建的,截止日期为16小时。
就是这样,2019-06-06 08:00:00
答案 0 :(得分:0)
经过大量的寻找答案之后,我发现了一个可以解决我的问题的函数。
function addRollover($givenDate, $addtime, $dayStart, $dayEnd, $weekDaysOnly) {
//Break the working day start and end times into hours, minuets
$dayStart = explode(',', $dayStart);
$dayEnd = explode(',', $dayEnd);
//Create required datetime objects and hours interval
$datetime = new DateTime($givenDate);
$endofday = clone $datetime;
$endofday->setTime($dayEnd[0], $dayEnd[1]); //set end of working day time
$interval = 'PT'.$addtime.'H';
//Add hours onto initial given date
$datetime->add(new DateInterval($interval));
//if initial date + hours is after the end of working day
if($datetime > $endofday)
{
//get the difference between the initial date + interval and the end of working day in seconds
$seconds = $datetime->getTimestamp()- $endofday->getTimestamp();
//Loop to next day
while(true)
{
$endofday->add(new DateInterval('PT24H'));//Loop to next day by adding 24hrs
$nextDay = $endofday->setTime($dayStart[0], $dayStart[1]);//Set day to working day start time
//If the next day is on a weekend and the week day only param is true continue to add days
if(in_array($nextDay->format('l'), array('Sunday','Saturday')) && $weekDaysOnly)
{
continue;
}
else //If not a weekend
{
$tmpDate = clone $nextDay;
$tmpDate->setTime($dayEnd[0], $dayEnd[1]);//clone the next day and set time to working day end time
$nextDay->add(new DateInterval('PT'.$seconds.'S')); //add the seconds onto the next day
//if the next day time is later than the end of the working day continue loop
if($nextDay > $tmpDate)
{
$seconds = $nextDay->getTimestamp()-$tmpDate->getTimestamp();
$endofday = clone $tmpDate;
$endofday->setTime($dayStart[0], $dayStart[1]);
}
else //else return the new date.
{
return $endofday;
}
}
}
}
return $datetime;
}
谢谢大家。