Question

我编写查询并获取值

我已经在SQL Server 2012上尝试过此操作

;With CTE_ColorIndicator
AS
(
    select Name,Value,Report_Date,
    Dense_Rank() Over(Order by Report_Date DESC)Dno,
    (AVG(value)+(3*STDEV(value))) UpperLimit,
    (AVG(value)+(3*STDEV(value)))*0.85 Limit 
    from #Temp1 
    group by Name,value,Report_date
)

Select * 
from CTE_ColorIndicator 
where Dno <=90 and Dno > 7

“我希望聚合值可以代替“上限”和“限制”列” “但是输出在上限和限制列中显示'NULL'值”

Answer 1

您正在按value分组。因此，没有定义标准偏差。我认为您打算将子查询设为：

select Name, Report_Date,
       Dense_Rank() Over (Order by Report_Date DESC) as Dno,
       (AVG(value) + 3 * STDEV(value)) as UpperLimit,
       (AVG(value) + 3 * STDEV(value)) * 0.85 as Limit 
from #Temp1 
group by Name, Report_date

获取“空”值以聚合数据

1 个答案: