Question

我用pyqt5程序制作了一个虚拟键盘，现在我有一个输入，并且按顺序有键盘1 2 3 4 5 6 7 8 9 0 a b c d e f g h i j ........... 设现在我希望键盘在每个突出显示的按钮都处于自动循环中当输入被触发时，我想选择该按钮，然后再次循环以重新启动

我无法正常工作请帮助我

我试图在python代码中循环并触发按钮的输入，然后我添加time.sleep（time）和输出比我在time.sleep中添加的时间晚了大约一秒钟，所有按钮的输出都在触发每个按钮的时间相同....

from  PyQt5.QtWidgets  import *
from  PyQt5.uic  import  loadUi
import sys
from  matplotlib.backends.backend_qt5agg  import  ( NavigationToolbar2QT  as  NavigationToolbar )
import matplotlib.animation as animation
import matplotlib as plt
from matplotlib.figure import Figure
import  numpy  as  np
import  random
from lineEdit import QLabel
from time import sleep

n=200 #frames
interval=60

global init
init = ""

def autotype(button,output):
    for i in button:
        for j in output:
            i.setStyleSheet("background-color: red")
            i.clicked.connect(j)
            sleep(0.5)

class  MatplotlibWidget ( QMainWindow ):


    def  __init__ ( self ):
        QMainWindow . __init__ ( self )
        loadUi ( "qt_desginer.ui" , self )
        self.setWindowTitle ( "Brain Input processer" )
        #self . pushButton_generate_random_signal . clicked . connect ( self . update_graph )
        self.update_graph()
        self.addToolBar ( NavigationToolbar(self.MplWidget.canvas,self))

        self.button_1n = 1
        self.button_2n = 2
        self.button_3n = 3
        self.button_4n = 4
        self.button_5n = 5


        button = [ self.button_1,self.button_2,self.button_3,self.button_4,self.button_5 ]
        output = [ self.button_click1,self.button_click2,self.button_click3,self.button_click4,self.button_click5]

        for x in button:
            x.clicked.connect(lambda: autotype(button,output))

    def keyboardinput(self,output):
        a = output
        global init
        concat =  init + a
        self.QLabel.setText(concat)
        init = concat

    def keyboardinputclear(self):
        self.QLabel.clear()


    def button_click1(self):
        self.keyboardinput(str(self.button_1n))
        #self.QLabel.setText(str(self.button_1n))


    def button_click2(self):
        self.keyboardinput(str(self.button_2n))
        #self.QLabel.setText(str(self.button_2n))

    def button_click3(self):
        self.keyboardinput(str(self.button_3n))
        #self.QLabel.setText(str(self.button_3n))

    def button_click4(self):
        self.keyboardinput(str(self.button_4n))
        #self.QLabel.setText(str(self.button_4n))

    def button_click5(self):
        self.keyboardinput(str(self.button_5n))
        #self.QLabel.setText(str(self.button_5n))



app  =  QApplication ([])
window  =  MatplotlibWidget ()
window . show ()
app . exec_ ()

我希望每个突出显示的按钮都能自动进入键盘循环当输入被触发时，我想选择该按钮，然后再次循环以重新启动

我做了一个虚拟键盘，我想用输入来控制，以便我的键盘按钮像1,2,3,4,5那样循环运行

0 个答案: