Question

我正在为学校项目编写Python代码。该程序将根据用户输入绘制多个圆圈（2-6个圆圈）。我已经做到了，但是现在需要根据用户输入绘制多行圆圈。例如，如果用户选择3个圆，则我需要按3个圆绘制3个圆。

#import tkinter and turtle
import tkinter as tk
from turtle import *
#ask for user input using tkinter
from tkinter import simpledialog
application_window = tk.Tk()
answer = simpledialog.askinteger('Request', 'number of circles(2-6)?', 
parent=application_window, minvalue=2, maxvalue=6)
#set position of turtle and define turtle
t = Turtle()
t.penup()
t.setpos(-200,-200)
t.pendown()
#draw appropriate number of circles using loop
i = 2
for i in range (answer):
   circle(30)
   penup()
   forward(60)
   pendown()
   i = +1

Answer 1

别让我们做功课。告诉我们问题，告诉我们您尝试过的内容，然后提出问题。例如，“如何使乌龟画三行圆？”

围绕您已经拥有的for循环和另一个for循环。每次外部循环运行时，内部循环将运行以创建一行，然后在下一次迭代之前将乌龟向下移动。

#import tkinter and turtle
import tkinter as tk
from turtle import *
#ask for user input using tkinter
from tkinter import simpledialog
application_window = tk.Tk()
answer = simpledialog.askinteger('Request', 'number of circles(2-6)?', 
parent=application_window, minvalue=2, maxvalue=6)
#set position of turtle and define turtle
t = Turtle()
t.penup()
t.setpos(-200,-200)
t.pendown()

#draw appropriate number of circles using loop
for row in range(answer):
    for col in range(answer):
        circle(30)
        penup()
        forward(60) # must be undone after loop
        pendown()

    penup()
    backward(60) # undo the backward on line 20
    backward(60 * col) # go backwards the length of the diameter times the number of circles
    right(90) # turn right 90 degrees
    forward(60) # forward the length of one diameter
    left(90) # turn back left 90 degrees
    pendown()

Answer 2

我提供@JacksonH解决方案的替代解决方案有两个原因：首先，如果您使用的是Python 3（并且应该应该是），那么您就不需要掌握了simpledialog在tkinter之外，请改用Python 3 turtle的numinput()（和textinput()）；其次，美学目标应该是使乌龟尽可能少地移动以达到您的结果，即使这需要更多，更智能的代码。观察此解决方案与其他解决方案的绘制方式之间的区别：

from turtle import Screen, Turtle

# Ask for user input

DEFAULT_COUNT = 3

screen = Screen()
answer = screen.numinput('Request', 'number of circles(2-6)?', default=DEFAULT_COUNT, minval=2, maxval=6)

if answer is None:
    answer = DEFAULT_COUNT
else:
    answer = int(answer)  # int for range()

# define turtle and set position of turtle
turtle = Turtle()
turtle.speed('fast')  # because I have little patience
turtle.penup()
turtle.setpos(-200, -200)

direction = 1

# draw appropriate number of circles using nested loops
for row in range(answer - 1, -1, -1):  # loop backward to use last iteration as a flag

    for column in range(answer - 1, -1, -1):
        turtle.pendown()
        turtle.circle(30 * direction)
        turtle.penup()
        if column:
            turtle.forward(60)  # not done final time

    if row:  # every time but the last
        turtle.left(90 * direction)  # turn +/-90 degrees
        turtle.forward(60)  # forward the length of one diameter
        turtle.left(90 * direction)  # turn +/-90 degrees

        direction *= -1  # reverse our sense of direction

turtle.hideturtle()
screen.exitonclick()

根据用户输入绘制圆

2 个答案: