Question

该函数应该循环，每次将圆的大小减小10并绘制一个新圆，直到大小小于或等于0.我缺少什么

def circle(x):
    turtle.up()
    turtle.goto(0,0)
    turtle.down()
    turtle.color("blue")
    turtle.circle(x)
    if x>0:
        turtle.up()
        turtle.goto(0,0)
        turtle.down()
        turtle.color("blue")
        turtle.circle(x-10)
    else:
        turtle.up()
        turtle.goto(0,0)
        turtle.down()
        turtle.color("blue")
        turtle.circle(x)
print(circle(80))

Answer 1

这是一个工作版本。添加了递归circle(x-10)，删除了冗余代码，添加了turtle.done()以阻止应用崩溃。

import turtle
def circle(x):
    turtle.up()
    turtle.goto(0,0)
    turtle.down()
    turtle.color("blue")
    turtle.circle(x)
    if x>0:        
        circle(x-10)    
circle(80)
turtle.done()

Answer 2

带有显式循环的版本：

import turtle
def circle(x):    
    while x > 0: 
        turtle.up()
        turtle.goto(0,0)
        turtle.down()
        turtle.color("blue")
        turtle.circle(x)
        x -= 10;
circle(80)
turtle.done()

Answer 3

def ring_draw(dia,x0,y0):
    to_return=[]
    rad = dia / 2
    for x in xrange(x0+(rad+2)):
        for y in xrange(y0+(rad+2)):
            z0 = abs(x - x0)
            z1 = abs(y - y0)
            z2 = z0**2 + z1**2
            if rad**2 >= z2:
                to_return.append([x,y])

绘制圆圈Python

3 个答案: