我需要制作一个球掉落并且不能击中地面的游戏,并且您必须使其再次弹跳才能击中地面,但是我不知道如何在单击鼠标时使球跳起来!
我如何对鼠标在屏幕上的点击做出反应?
var canvas, ctx, container;
canvas = document.createElement('canvas');
ctx = canvas.getContext("2d");
var ball;
// Velocity y - randomly set
var vy;
var gravity = 0.5;
var bounce = 0.7;
var xFriction = 0.1;
function init() {
setupCanvas();
vy = (Math.random() * -15) + -5;
ball = {
x: canvas.width / 2,
y: 100,
radius: 20,
status: 0,
color: "red"
};
}
function draw() {
ctx.clearRect(0, 0, canvas.width, canvas.height);
ctx.beginPath();
ctx.arc(ball.x, ball.y, ball.radius, 0, Math.PI * 2, false);
ctx.fillStyle = ball.color;
ctx.fill();
ctx.closePath()
ballMovement();
}
setInterval(draw, 1000 / 35);
function ballMovement() {
ball.y += vy;
vy += gravity;
if (ball.x + ball.radius > canvas.width || ball.x - ball.radius < 0) {
vx *= -1;
}
if (ball.y + ball.radius > canvas.height) {
ball.y = canvas.height - ball.radius;
vy *= -bounce;
vy = 0;
if (Math.abs(vx) < 1.1)
vx = 0;
xF();
}
}
function setupCanvas() { //setup canvas
container = document.createElement('div');
container.className = "container";
canvas.width = window.innerWidth;
canvas.height = window.innerHeight;
document.body.appendChild(container);
container.appendChild(canvas);
ctx.strokeStyle = "#ffffff";
ctx.lineWidth = 2;
}
答案 0 :(得分:0)
您只需要按如下方式制作事件监听器
window.addEventListener('click', function(event) {
//code here
})
//but if you want it so it's just on the canvas
canvas.addEventListener('click', function(event) {
//code here
})