Python二次公式无法正确计算

时间:2019-04-06 21:26:42

标签: python python-3.x python-module

这是我运行程序的主文件:

import math
import Disc

def main():

    coeffA = int(input('Enter the coefficient A: '))
    coeffB = int(input('Enter the coefficient B: '))
    coeffC = int(input('Enter the coefficient C: '))

    disc = Disc.discriminant(coeffA, coeffB, coeffC)

    while coeffA != 0:


        if disc > 0:

            solutionOne = (-coeffB + math.sqrt(disc)) / (2 * coeffA)
            solutionTwo = (-coeffB - math.sqrt(disc)) / (2 * coeffA)

            print('Solutions are: ' + str(solutionOne) + ' and ' + str(solutionTwo))

            coeffA = int(input('Enter the coefficient A: '))
            coeffB = int(input('Enter the coefficient B: '))
            coeffC = int(input('Enter the coefficient C: '))

        elif disc == 0:

            solutionOne = -coeffB / (2 * coeffA)

            print('Solution is: ' + str(solutionOne))

            coeffA = int(input('Enter the coefficient A: '))
            coeffB = int(input('Enter the coefficient B: '))
            coeffC = int(input('Enter the coefficient C: '))

        elif disc < 0:

            print('Equation has two complex roots.')

            coeffA = int(input('Enter the coefficient A: '))
            coeffB = int(input('Enter the coefficient B: '))
            coeffC = int(input('Enter the coefficient C: '))

    else:
        print('Program ended.')


# End of the main function

main()

这是Disc.py文件,在其中计算出判别式值以便在main()函数中使用:

def discriminant(coeffA, coeffB, coeffC):

    value = (coeffB ** 2) - (4 * coeffA * coeffC)

    return value

这是运行程序时的输出:

Enter the coefficient A: 1
Enter the coefficient B: 2
Enter the coefficient C: -8
Solutions are: 2.0 and -4.0
Enter the coefficient A: 1
Enter the coefficient B: -12
Enter the coefficient C: 36
Solutions are: 9.0 and 3.0
Enter the coefficient A: 2
Enter the coefficient B: 9
Enter the coefficient C: -5
Solutions are: -0.75 and -3.75
Enter the coefficient A: 4
Enter the coefficient B: 6
Enter the coefficient C: 20
Solutions are: 0.0 and -1.5
Enter the coefficient A: 0
Enter the coefficient B: 0
Enter the coefficient C: 0
Program ended.

我期望上面的输入具有以下根源:

Run1: 2, -4

Run2: 6

Run3: .5, -5

Run4: 'Equation has two complex roots.'

当我运行程序时,在程序运行的最后3次中,输出是错误的,并且似乎在将判别式设置为大于0的值时,我希望它根据计算出的判别式来更改输出。预先感谢!

2 个答案:

答案 0 :(得分:0)

您似乎缺少一对方括号。 这应该可以修复错误:

if disc > 0:

            solutionOne = (-coeffB + math.sqrt(disc)) / (2 * coeffA)
            solutionTwo = (-coeffB - math.sqrt(disc)) / (2 * coeffA)

            print('Solutions are: ' + str(solutionOne) + ' and ' + str(solutionTwo))

            coeffA = int(input('Enter the coefficient A: '))
            coeffB = int(input('Enter the coefficient B: '))
            coeffC = int(input('Enter the coefficient C: '))

答案 1 :(得分:0)

找到了解决方案。我的判别函数在while语句之外,因此,当用户输入3个变量时,它将保留每个循环中计算出的第一个判别式,这就是为什么输出每次运行都会产生2个答案的原因。通过将判别函数的位置更改为while语句内部,它现在为while语句的每个循环重新计算判别式。这是解决此问题的正确代码:

import math
import Disc

def main():



    coeffA = int(input('Enter the coefficient A: '))

    while coeffA != 0:

        coeffB = int(input('Enter the coefficient B: '))
        coeffC = int(input('Enter the coefficient C: '))

        disc = Disc.discriminant(coeffA, coeffB, coeffC)

        if disc > 0:

            solutionOne = (-coeffB + math.sqrt(disc)) / (2 * coeffA)
            solutionTwo = (-coeffB - math.sqrt(disc)) / (2 * coeffA)

            print('Solutions are: ' + str(solutionOne) + ' and ' + str(solutionTwo))

            coeffA = int(input('Enter the coefficient A: '))

        elif disc == 0:

            solutionOne = -coeffB / (2 * coeffA)

            print('Solution is: ' + str(solutionOne))

            coeffA = int(input('Enter the coefficient A: '))

        elif disc < 0:

            print('Equation has two complex roots.')

            coeffA = int(input('Enter the coefficient A: '))

    print('Program ended.')


    # End of the main function

产生的正确输出代码如下:

Enter the coefficient A: 1
Enter the coefficient B: 2
Enter the coefficient C: -8
Solutions are: 2.0 and -4.0
Enter the coefficient A: 1
Enter the coefficient B: -12
Enter the coefficient C: 36
Solution is: 6.0
Enter the coefficient A: 2
Enter the coefficient B: 9
Enter the coefficient C: -5
Solutions are: 0.5 and -5.0
Enter the coefficient A: 4
Enter the coefficient B: 6
Enter the coefficient C: 20
Equation has two complex roots.
Enter the coefficient A: 0
Program ended.

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