如何计算python中数组中重复项的数量？

Question

我有一个密码验证程序，并将2条不同的错误消息导出到.txt文件，然后将每一行转换为一个数组。

.txt文件的外观如下-

2019-03-30 13:29:12.490929, Password < 6
2019-03-30 13:29:18.044002, Password > 14 
2019-03-30 13:42:38.230401, Password < 6
2019-03-30 13:42:40.741990, Password < 6

每次出现“ Password <6”和“ Password> 14”时，我将如何加起来并将它们分配给两个不同的变量？ 希望我解释得足够好，感谢您的帮助。

Answer 1

假定包含信息的文本文件称为test.txt

# extract all lines as a list
lines = [line.rstrip('\n') for line in open('test.txt', 'r')]

# set two variable counters
counter_6 = 0
counter_14 = 0

for line in lines:
    # split the lines into the needed parts
    # and access only the second, password part
    password_part = line.split(", ")[1]

    # increment for Password < 6
    if "< 6" in password_part:
        counter_6 += 1
    # increment for Password > 14
    elif "> 14" in password_part:
        counter_14 += 1

print(counter_6, counter_14)

希望这会有所帮助。