Question

我正在用C ++制作子手游戏，我即将完成，但是我遇到了一个主要问题。我必须让游戏只允许用户猜测4次，但是我的程序未注册正确的猜测数。

我尝试更改有关猜测的if和else语句中的变量以及条件。

#include <iostream>
#include <string>
#include <vector>

using namespace std;

int main() {
cout << "Welcome to hangman!" << endl;

char choice = 'y';

while (choice == 'y') {
    string word;
    cout << "Enter a word to guess: ";
    getline(cin, word);

    if (word.empty()) {
        cout << "The word should not be blank.\n";
        continue;
    }

    bool contain_space = false;
    for (char c : word) {
        if (isspace(c)) {
            contain_space = true;
            break;
        }
    }

    if (contain_space) {
        cout << "The word cannot contain spaces.\n";
        continue;
    }

    vector <bool> index;
    for (int i = 0; i < word.size(); i++) {
        index.push_back(false);
    }

    **int guess_correct = 0;**
    int guess_wrong = 4;
    char letter;

    while (guess_wrong >= 0 && guess_correct < word.size()) {
        bool valid_guess = true;
        cout << "Guess a letter." << endl;
        cin >> letter;
        for (int i = 0;i < word.size(); i++) {
            if (word[i] == letter) {
                valid_guess = true;
                index[i] = true;
                guess_correct++;
                break;

            }
            else {
                guess_wrong = guess_wrong - 1;
            }

        }

        for (int i = 0; i < word.size(); i++) {
            if (index[i] == true) {
                cout << word[i] << "\t";
            }
            else {
                cout << "___\t";
            }
        }
        cout << endl;
    }


    cout << "Would you like to play again? (y/n)" << endl;
    cin >> choice;
    cin.ignore();
}
return 0;
}

黑色刻度线表示我所停留的代码段的开头。每次我运行它时，它都会让我以正确的猜测经历游戏，但是错误的猜测不允许出现4。

Answer 1

对于不匹配单词中的每个字母，您要递减guess_wrong，对于“整体猜测”，请不要递减一次。

您可能想将guess_wrong = guess_wrong - 1; // aka guess_wrong--移出for循环，而只进行if (!valid_guess)。

我正在制作一个子手游戏，我需要帮助弄清楚为什么它无法正常运行

1 个答案: