我想用下面的代码片段Map
a 覆盖Map
b 。我目前正在清除 b 的内容,然后逐一设置条目。编写copyMap
函数的更有效的方式(更少的垃圾,更快等)是什么?
const a = new Map([[1, 2], [2, 10], [3, 20]]);
const b = new Map([[1,5]]);
// I want to copy a into b, at the end b should look like
// b = new Map([[1, 2], [2, 10], [3, 20]]);
console.log(a,b);
function copyMap(srcMap, destMap) {
destMap.clear();
// Maybe this loop could be done in a single call somehow?
for(let item of srcMap) {
destMap.set(item[0], item[1]);
}
}
copyMap(a, b);
// a and b should have same entries
console.log('a: ',[...a.entries()], 'b: ', [...b.entries()]);
答案 0 :(得分:0)
你可以做
modelspace.add_text(label, dxfattribs={'layer': 'TEXTLAYER', 'text_generation_flag': 2, 'height': 4}).set_pos((cx, cy), align='CENTER')
,您需要为b删除const声明