Question

我正在尝试从用户输入中构建一个列表，直到他们说“是”为止。我已经按照下面的说明进行了操作，但是很快意识到我将不得不继续写一行代码多次，直到允许用户输入为止。但是，其想法是让用户构建一个数字列表，直到他们对数字列表感到厌烦为止，以便稍后在程序中引用它。因此，基本上我想引用第6行，直到遇到“是”为止。

play_num = int
play_num = input('Give me a number.')
play_num = int(play_num) + int(1)
choice1 = str
AnnoyList = []
choice1 = input ("You said " + str(play_num) + " right? ")
if (choice1.lower is "no"):
    AnnoyList.append(play_num)
    play_num = input ("Oh, sorry what was it then? ")
    AnnoyList.append(play_num)
if (choice1.lower is "yes")

Answer 1

查看while循环。设置一个等于True的变量并循环直到用户输入no，然后将其设置为False。

或者，如果您知道要循环多少次，请查看for循环。

https://docs.python.org/3/tutorial/controlflow.html#break-and-continue-statements-and-else-clauses-on-loops

Answer 2

当用户输入yes时，使用while循环使用break语句。在这里阅读有关它们的信息：Control Flow Statements

您的代码将如下所示

AnnoyList = []
choice1 = "no"
play_num = input('Give me a number.')
while choice1.lower()!="yes":# notice the parenthesis

    play_num = int(play_num) + (1)
    choice1 = input ("You said " + str(play_num) + " right? ")
    if (choice1.lower() == "no"):
         AnnoyList.append(play_num)
         play_num = input ("Oh, sorry what was it then? ")

Python：循环引用一行代码，直到满足条件

2 个答案: