Question

我的报告按用户分为几个部分，然后再按日期划分。

报告如下：

ACCOUNT: 1
DATE             BALANCE
04/04/18     11,421,231.94
04/05/18     16,545,275.32

ACCOUNT: 2
DATE             BALANCE
04/04/18      4,822,236.39
04/05/18      4,445,253.14-

我需要在今天的余额和日期

旁边打印用户的帐号

foreach Account in Accounts:
    with open ('C:\intersum.recap.txt') as f:
      for line in f:
        if Account in line:
            if "04/05/18" in line:
                print(line) + Account

如何编写我的代码，以便每次在帐户中找到帐号时，它会在今天的余额中打印该帐户值？

理想情况下，输出为：

帐户1 04/05/18 4,445,253.14 -

Answer 1

使用正则表达式。

import re
import datetime
toDayDate = datetime.datetime.now().strftime("%d/%m/%y")

with open ('C:\intersum.recap.txt') as f:
    s = f.read()                      #Read file and get content. 

account = re.findall("(?:ACCOUNT:).*", s)
balance =  re.findall("(?:{0}).*".format(toDayDate), s)

for i in zip(account, balance):
    print(i)

<强>输出：

('ACCOUNT: 1', '10/04/18     11,421,231.94')
('ACCOUNT: 2', '10/04/18      4,822,236.39')

Answer 2

我最终使用以下内容解决了我的问题：

Accounts = ['1', '2', '3', '4', '5']
for Account in Accounts:
    with open ('C:\intersum.recap.txt') as f:
        for line in f:
            if "ACCOUNT: " + Account in line:
                #print(line)
                TAccount = Account
                for line in f:
                    if "04/05/18" in line:
                        #print(line)
                        Transaction = line
                        print(TAccount + " " + line)
                        break

满足两个条件时打印行

2 个答案: