我的EBNF语法规范的解析器组合器使堆栈溢出。为什么?我该如何解决?
我正在尝试通过scala库中的组合器为EBNF syntax定义解析器。实际上,该代码构建了语法的AST,但是我已经去除了这些位,并内联了一种实用程序方法,以便产生MVCE(如下所示)。
运行时编写的代码会产生堆栈溢出(也在下面)。我无法理解的是,它似乎在解析的跳过空白部分溢出。如何解决此错误?如果无法解析EBNF语法,那真的很不幸,我打算为此开发一些工具。
package org.benknoble.ebnf
import scala.util.parsing.combinator._
class EbnfParserSimple extends RegexParsers {
def nonterminal: Parser[String] = """<[^>]+>""".r
def goesTo: Parser[String] = """::="""
def epsilon: Parser[String] = "ε"
def terminal: Parser[String] = "\"[^\"]+\"".r
def sequence: Parser[String] =
exp ~ exp ^^ { case left ~ right => left + right }
def alternation: Parser[String] =
exp ~ "|" ~ exp ^^ { case left ~ _ ~ right => left + "|" + right }
def opt: Parser[String] =
"[" ~ exp ~ "]" ^^ { case lb ~ e ~ rb => lb + e + rb }
def repetition: Parser[String] =
"{" ~ exp ~ "}" ^^ { case lb ~ e ~ rb => lb + e + rb }
def group: Parser[String] =
"(" ~ exp ~ ")" ^^ { case lb ~ e ~ rb => lb + e + rb }
def exp: Parser[String] =
(epsilon
| terminal
| nonterminal
| sequence
| alternation
| opt
| repetition
| group)
def rule: Parser[String] = nonterminal ~ goesTo ~ exp ~ ";" ^^ {
case nt ~ delim ~ e ~ semi => nt + delim + e + semi
}
def join[A](sep: String, list: Seq[A]): String = list match {
case h :: t => h.toString() + t.foldLeft("")(_.toString() + sep + _.toString())
case Nil => ""
}
def root: Parser[String] = phrase(
rep(rule) ^^ {
case rules =>
val joined = join(" ;\n", rules)
if (joined.isEmpty)
joined
else
joined + " ;"
}
)
}
object Main extends App {
val parser = new EbnfParserSimple()
val grammar = """<A> ::= ["a"|ε]"c" ; """
// <B> ::= <A>"b" ;
// <C> ::= {<B>}"$" ;
// <D> ::= "a""b""d" ;
// <E> ::= ("a"|"b")"c" ;
// """
val rule = parser.root
println(parser.parse(rule, grammar))
}
完整日志可以找到as a Gist。
[info] Loading project definition from /Users/Knoble/loner/project
[info] Loading settings for project root from build.sbt ...
[info] Set current project to loner (in build file:/Users/Knoble/loner/)
[info] Set current project to ebnf (in build file:/Users/Knoble/loner/)
[info] Running org.benknoble.ebnf.Main
[error] (run-main-0) java.lang.StackOverflowError
[error] java.lang.StackOverflowError
[error] at java.util.regex.Pattern.compile(Pattern.java:1673)
[error] at java.util.regex.Pattern.<init>(Pattern.java:1351)
[error] at java.util.regex.Pattern.compile(Pattern.java:1028)
[error] at scala.util.matching.Regex.<init>(Regex.scala:226)
[error] at scala.collection.immutable.StringLike.r(StringLike.scala:284)
[error] at scala.collection.immutable.StringLike.r$(StringLike.scala:284)
[error] at scala.collection.immutable.StringOps.r(StringOps.scala:33)
[error] at scala.collection.immutable.StringLike.r(StringLike.scala:273)
[error] at scala.collection.immutable.StringLike.r$(StringLike.scala:273)
[error] at scala.collection.immutable.StringOps.r(StringOps.scala:33)
[error] at org.benknoble.ebnf.EbnfParserSimple.terminal(EbnfParser_strings.scala:13)
[error] at org.benknoble.ebnf.EbnfParserSimple.$anonfun$exp$1(EbnfParser_strings.scala:32)
[error] at scala.util.parsing.combinator.Parsers$Parser.p$lzycompute$1(Parsers.scala:253)
[error] at scala.util.parsing.combinator.Parsers$Parser.p$4(Parsers.scala:253)
[error] at scala.util.parsing.combinator.Parsers$Parser.$anonfun$append$2(Parsers.scala:254)
[error] at scala.util.parsing.combinator.Parsers$Failure.append(Parsers.scala:202)
[error] at scala.util.parsing.combinator.Parsers$Parser.$anonfun$append$1(Parsers.scala:254)
[error] at scala.util.parsing.combinator.Parsers$$anon$3.apply(Parsers.scala:222)
[error] at scala.util.parsing.combinator.Parsers$Parser.$anonfun$append$1(Parsers.scala:254)
[...]
[error] at scala.util.parsing.combinator.Parsers$$anon$3.apply(Parsers.scala:222)
[error] at scala.util.parsing.combinator.Parsers$Parser.$anonfun$append$1(Parsers.scala:254)
[error] at scala.util.parsing.combinator.Parsers$$anon$3.apply(Parsers.scala:222)
[error] at scala.util.parsing.combinator.Parsers$Parser.$anonfun$append$1(Parsers.scala:254)
[error] at scala.util.parsing.combinator.Parsers$$anon$3.apply(Parsers.scala:222)
[error] at scala.util.parsing.combinator.Parsers$Parser.$anonfun$append$1(Parsers.scala:254)
[error] at scala.util.parsing.combinator.Parsers$$anon$3.apply(Parsers.scala:222)
[error] at scala.util.parsing.combinator.Parsers$Parser.$anonfun$append$1(Parsers.scala:254)
[error] at scala.util.parsing.combinator.Parsers$$anon$3.apply(Parsers.scala:222)
[error] at scala.util.parsing.combinator.Parsers$Parser.$anonfun$flatMap$1(Parsers.scala:239)
[error] at scala.util.parsing.combinator.Parsers$$anon$3.apply(Parsers.scala:222)
[error] Nonzero exit code: 1
[error] (Compile / run) Nonzero exit code: 1
[error] Total time: 1 s, completed 12 mars 2019 21:11:15
答案 0 :(得分:1)
我最终可以通过techniques found in this answer删除左递归来解决我的问题。在下面找到工作代码。
我必须仔细考虑转换:特别是alternation.+ ^^ { _.reduce(_ + _) }
和sequence.+ ^^ { _.reduce(_ + _) }
-将这些转换回AST生成器可能并不容易(因为这些转换的构造函数只需要左右键即可) 。重复操作也让我有些困扰,但是没有提取辅助函数,这是唯一要做的事情。
package org.benknoble.ebnf
import scala.util.parsing.combinator._
class EbnfParserSimple extends RegexParsers {
def epsilon: Parser[String] = "ε"
def terminal: Parser[String] = "\"[^\"]+\"".r
def nonterminal: Parser[String] = """<[^>]+>""".r
def opt: Parser[String] =
"[" ~ exp ~ "]" ^^ { case lb ~ e ~ rb => lb + e + rb }
def repetition: Parser[String] =
"{" ~ exp ~ "}" ^^ { case lb ~ e ~ rb => lb + e + rb }
def group: Parser[String] =
"(" ~ exp ~ ")" ^^ { case lb ~ e ~ rb => lb + e + rb }
def alternation: Parser[String] =
chainl1(epsilon
| terminal
| nonterminal
| opt
| repetition
| group,
"|" ^^^ { (lb: String, rb: String) => lb + "|" + rb })
// exp ~ "|" ~ exp ^^ { case left ~ _ ~ right => left + "|" + right }
def sequence: Parser[String] =
alternation.+ ^^ { _.reduce(_ + _) }
// alternation ~ alternation ^^ { case lb ~ rb => lb + rb }
// exp ~ exp ^^ { case left ~ right => left + right }
def exp: Parser[String] =
sequence.+ ^^ { _.reduce(_ + _) }
def goesTo: Parser[String] = """::="""
def rule: Parser[String] = nonterminal ~ goesTo ~ exp ~ ";" ^^ {
case nt ~ delim ~ e ~ semi => nt + delim + e + semi
}
def join[A](sep: String, list: Seq[A]): String = list match {
case h :: t => h.toString() + t.foldLeft("")(_.toString() + sep + _.toString())
case Nil => ""
}
def root: Parser[String] = phrase(
rep(rule) ^^ {
case rules =>
val joined = join(" ;\n", rules)
if (joined.isEmpty)
joined
else
joined + " ;"
}
)
}
object Main extends App {
val parser = new EbnfParserSimple()
val grammar = """<A> ::= ["a"|ε]"c" ; """
// <B> ::= <A>"b" ;
// <C> ::= {<B>}"$" ;
// <D> ::= "a""b""d" ;
// <E> ::= ("a"|"b")"c" ;
// """
val rule = parser.root
println(parser.parse(rule, grammar))
}