我有一个非常简单的代码段:
<?php
$fp = fopen(dirname(__FILE__).'/errorlog.txt', 'w');
fwrite($fp, "writing works..\n");
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, "http://10.0.0.1/url");
curl_setopt($ch, CURLOPT_VERBOSE, 1);
curl_setopt($ch, CURLOPT_STDERR, $fp);
print_r(curl_exec($ch));
print_r(curl_errno($ch));
print_r(curl_getinfo($ch));
print_r(curl_version());
curl_close($ch);
fclose($fp);
?>
总体上可以正常工作,但是当前在我使用的特定环境中已损坏。 curl_errno
返回2
,即CURLE_FAILED_INIT
。
我正在尝试调查是否存在系统问题here,但我想知道是否可以通过某种方式调试代码,这是什么问题。
类似于this问题中的答案不会产生任何输出(文件errorlog.txt
很容易发现为空..我猜这是我想的,因为libcurl甚至无法初始化)。
curl_getinfo()
的输出是无用的,因为它永远不会执行请求。这是curl_version的输出:
[version_number] => 466176
[age] => 3
[features] => 558781
[ssl_version_number] => 0
[version] => 7.29.0
[host] => x86_64-redhat-linux-gnu
[ssl_version] => NSS/3.28.4
[libz_version] => 1.2.7
[protocols] => Array
(
[0] => dict
[1] => file
[2] => ftp
[3] => ftps
[4] => gopher
[5] => http
[6] => https
[7] => imap
[8] => imaps
[9] => ldap
[10] => ldaps
[11] => pop3
[12] => pop3s
[13] => rtsp
[14] => scp
[15] => sftp
[16] => smtp
[17] => smtps
[18] => telnet
[19] => tftp
)
有人有指针吗?
谢谢