我试图从C代码调用DynamoDB低级API。这是我的代码
#include <stdio.h>
#include <curl/curl.h>
int main(void)
{
CURL *curl;
CURLcode res;
curl = curl_easy_init();
if(curl) {
struct curl_slist *chunk = NULL;
chunk = curl_slist_append(chunk, "Host: dynamodb.us-east-1.amazonaws.com;");
chunk = curl_slist_append(chunk, "Accept-Encoding: identity;");
chunk = curl_slist_append(chunk, "Content-Length: 53;");
chunk = curl_slist_append(chunk, "User-Agent: CustomApp42;");
chunk = curl_slist_append(chunk, "Content-Type: application/x-amz-json-1.0;");
chunk = curl_slist_append(chunk, "Authorization: AWS4-HMAC-SHA256 Credential=<Credential>, SignedHeaders=<Headers>, Signature=<signature>;");
chunk = curl_slist_append(chunk, "X-Amz-Date: 4.4.2016 ;");
chunk = curl_slist_append(chunk, "X-Amz-Target: DynamoDB_20120810.GetItem;");
res = curl_easy_setopt(curl, CURLOPT_HTTPHEADER, chunk);
curl_easy_setopt(curl, CURLOPT_URL, "dynamodb.us-east-1.amazonaws.com");
curl_easy_setopt(curl, CURLOPT_VERBOSE, 1L);
curl_easy_setopt(curl, CURLOPT_POSTFIELDS, "{\"TableName\":\"Pets\",\"Key\":{\"AnimalType\":{\"S\": \"Dog\"},\"Name\": {\"S\": \"Fido\"}}}");
res = curl_easy_perform(curl);
/* Check for errors */
if(res != CURLE_OK)
fprintf(stderr, "curl_easy_perform() failed: %s\n",
curl_easy_strerror(res));
/* always cleanup */
curl_easy_cleanup(curl);
/* free the custom headers */
curl_slist_free_all(chunk);
}
return 0;
}
但是在运行时会产生错误
HTTP/1.1 400 Bad Request
我主要面对两个问题。
答案 0 :(得分:0)
您是否可以使用AWS SDK for C++?它将为您完成所有这些繁重的工作。实际上,即使您正在制作C程序,也可以将extern C library结构公开给您需要的AWS SDK调用。因此,无论哪种方式,我建议使用AWS SDK for C ++进行编码,并创建一个extern C库包装器,以防您需要将主程序编译为C程序。