Question

根据2位选择输入（M），移位寄存器为：00-无更改，01-并行负载，10-左旋转，11-右移位（带SI）。我不确定并行加载的含义，并且我确定为多路复用器实例化代码的方式是不正确的（就使其执行移位，旋转等而言）。模拟测试平台时，我的Q值得到Xs。我撞墙了，不确定自己在做什么。

// Shift reg
module shift_reg4(
 input  clk,
 input  reset,
 input  [3:0] din,
 input  [1:0] M,
 input        SI,
 output [3:0] Q);

// wires to interconnect the 4-mux's to the 4 D-FF's
wire w3,w2,w1,w0;

mux4_to_1 m0 (.I({Q[3], Q[2], Q[1], Q[0]}),.S(M),.Y(w0));
mux4_to_1 m1 (.I(({din[3], din[2], din[1], din[0]}),.S(M),.Y(w1));
mux4_to_1 m2 (.I({Q[3], Q[1], din[2], Q[2]}),.S(M),.Y(w2));
mux4_to_1 m3 (.I({SI, din[3], din[2], din[1]}),.S(M),.Y(w3));

d_ff u0 (.clk(clk),.reset(reset),.D(w0),.Q(Q[0]));
d_ff u1 (.clk(clk),.reset(reset),.D(w1),.Q(Q[1]));
d_ff u2 (.clk(clk),.reset(reset),.D(w2),.Q(Q[2]));
d_ff u3 (.clk(clk),.reset(reset),.D(w3),.Q(Q[3]));

endmodule

//D-FlipFlop (Provided)
module d_ff(
input clk,
input reset,
input D,
output reg Q
);

 always @(posedge clk, posedge reset) begin
    if(reset == 1'b1)
        Q <= 1'b0;
    else
        Q <= D;
  end

endmodule

// 4-to-1 mux (Provided)
module mux4_to_1( 
 input [3:0] I, 
 input [1:0] S, 
 output reg Y);

always @(I,S)
    case(S)
        2'b00: Y = I[0];
        2'b01: Y = I[1];
        2'b10: Y = I[2];
        2'b11: Y = I[3];
        default: Y = I[0];
    endcase
endmodule

// Hint that was also provided for 16-bit
case(M)
    2'b00: Q <= Q;
    2'b01: Q <= din;
    2'b10: Q <= {SI,Q[15:1];
    2'b11: Q <= {Q[14:0], Q[15]};
    default: Q <= Q;
endcase

// My guess based on that hint is that the mux should be instantiated as:
mux4_to_1 m0 (.I(Q[3:0]),.S(M),.Y(w0));
mux4_to_1 m1 (.I(din[3:0]),.S(M),.Y(w1));
mux4_to_1 m2 (.I({Q[2:0], Q[3]}),.S(M),.Y(w2));
mux4_to_1 m3 (.I({SI, Q[3:1]}),.S(M),.Y(w3));

//This is my test bench for the shift reg (provided) but I'm not getting
//a value for Q
module shift_reg4_tb;

// Inputs
reg clk, reset, SI;
reg [3:0] D;
reg [1:0] M;

// Outputs
wire [3:0] Q;

// Instantiate the Unit Under Test (UUT)
shift_reg4 uut (
    .clk(clk), 
    .reset(reset), 
    .din(D), 
    .M(M), 
    .SI(SI), 
    .Q(Q)
);

// Generate Clock with a 10 ns period
always 
    #5 clk = ~clk;

// Initialize Inputs
initial begin
    $timeformat(-9, 1, " ns", 6);
    clk = 0;  reset = 0;  M = 0; D = 0; SI = 0;  

    //These two clocks take care of reset
    @(negedge clk)
        {reset,M,D,SI} = 8'b1_xx_xxxx_x;
    @(negedge clk)
        {reset,M,D,SI} = 8'b0_xx_xxxx_x;

    //Exercise the "load" function with D = 0xC(1100). Note SIis don't care
    @(negedge clk)
        {reset,M,D,SI} = 8'b0_01_1100_x;

    //Exercise the "no change" function. Note both D and SI are don't care
    @(negedge clk)
        {reset,M,D,SI} = 8'b0_00_xxxx_x;

    //Exercise the "shift right" function with SI = 0. Note D is don't care
    @(negedge clk)
        {reset,M,D,SI} = 8'b0_11_xxxx_0;

    //Exercise the "shift right" function with SI = 1. Note D is don't care
    @(negedge clk)
        {reset,M,D,SI} = 8'b0_11_xxxx_1;

    //Exercise the "no change" function. Note both D and SI are don't care
    @(negedge clk)
        {reset,M,D,SI} = 8'b0_00_xxxx_x;

    //Exercise the "rotate left" function. Note both D and SI are don't care
    @(negedge clk)
        {reset,M,D,SI} = 8'b0_10_xxxx_x;

    //Exercise the "rotate left" function. Note both D and SI are don't care
    @(negedge clk)
        {reset,M,D,SI} = 8'b0_10_xxxx_x;

    //Exercise the "no change" function. Note both D and SI are don'tcare
    @(negedge clk)
        {reset,M,D,SI} = 8'b0_00_xxxx_x;
    $finish;

不确定我是否为4位移位寄存器正确实现了Verilog代码

0 个答案: