Question

我有一些数据集，看起来像它们由形成双峰图的两个正态分布的叠加组成。我想为这些数据集的分布估计最合适的参数。通常，我会使用fitdistrplus程序包，但找不到分配函数来提供其算法。

有人可以把我指向一个方向还是建议我自己去做？

Answer 1

对this question的响应看起来像是在您的查询中一样。我在这里重复他们的代码：

library(mixdist)  

#Build data vector "x" as a mixture of data from 3 Normal Distributions  
x1 <- rnorm(1000, mean=0, sd=2.0)  
x2 <- rnorm(500, mean=9, sd=1.5)  
x3 <- rnorm(300, mean=13, sd=1.0)  
x <- c(x1, x2, x3)  

#Plot a histogram (you'll play around with the value for "breaks" as    
#you zero-in on the fit).   Then build a data frame that has the  
#bucket midpoints and counts.  
breaks <- 30  
his <- hist(x, breaks=breaks)  
df <- data.frame(mid=his$mids, cou=his$counts)  
head(df)  

#The above Histogram shows 3 peaks that might be represented by 3 Normal  
#Distributions.  Guess at the 3 Means in Ascending Order, with a guess for  
#the associated 3 Sigmas and fit the distribution.  
guemea <- c(3, 11, 14)  
guesig <- c(1, 1, 1)  
guedis <- "norm"  
(fitpro <- mix(as.mixdata(df), mixparam(mu=guemea, sigma=guesig), dist=guedis))  

#Plot the results  
plot(fitpro, main="Fit a Probability Distribution")  
grid()  
legend("topright", lty=1, lwd=c(1, 1, 2), c("Original Distribution to be Fit", "Individual Fitted Distributions", "Fitted Distributions Combined"), col=c("blue", "red", rgb(0.2, 0.7, 0.2)), bg="white")  

===========================  


Parameters:  
      pi     mu  sigma  
1 0.5533 -0.565 1.9671  
2 0.2907  8.570 1.6169  
3 0.1561 12.725 0.9987  

Distribution:  
[1] "norm"  

Constraints:  
   conpi    conmu consigma   
  "NONE"   "NONE"   "NONE"

使双模/两高斯分布适合R中的数据集

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