我有一个字符串数组。如何找到不等于零的元素并打印这些字符串？我该怎么做呢？
这是我想看到的：
Port Align-Err FCS-Err Xmit-Err Rcv-Err UnderSize OutDiscards "
Gi0/16 0 116 0 116 0 56
Gi0/3 0 0 23 0 0 315887
Po1 0 232464 0 232464 0 21331230
我的数组：
array = [
"Port Align-Err FCS-Err Xmit-Err Rcv-Err UnderSize OutDiscards ",
"Gi0/1 0 0 0 0 0 212086 ",
"Gi0/2 0 0 0 0 0 184832 ",
"Gi0/3 0 0 23 0 0 315887 ",
"Gi0/4 0 0 0 0 0 253439 ",
"Gi0/5 0 0 0 0 0 135034 ",
"Gi0/6 0 0 0 0 0 132617 ",
"Gi0/7 0 0 0 0 0 5816 ",
"Gi0/8 0 0 0 0 0 12266 ",
"Gi0/9 0 0 0 0 0 573217 ",
"Gi0/10 0 0 0 0 0 844880 ",
"Gi0/11 0 0 0 0 0 264766 ",
"Gi0/12 0 0 0 0 0 197496 ",
"Gi0/13 0 0 0 0 0 0 ",
"Gi0/14 0 0 0 0 0 372725 ",
"Gi0/15 0 0 0 0 0 14260434 ",
"Gi0/16 0 116 0 116 0 56 ",
"Gi0/17 0 0 0 0 0 6905901 ",
"Gi0/18 0 0 0 0 0 333387 ",
"Po1 0 232464 0 232464 0 21331230 ",
]
答案 0 :(得分：1)
ll= [ x.split() for x in array]
df = pd.DataFrame(ll)
df.columns = df.iloc[0]
df = df.reindex(df.index.drop(0))
df[['Align-Err', 'FCS-Err', 'Xmit-Err', 'Rcv-Err', 'UnderSize', 'OutDiscards']] = df[['Align-Err', 'FCS-Err', 'Xmit-Err', 'Rcv-Err', 'UnderSize', 'OutDiscards']].astype(int)
我找不到想要查找不等于0的元素的部分。什么元素？什么列？您每行都有零。
df = df[df != 0].dropna()
答案 1 :(得分：1)
# your code goes here
array = [
'Port Align-Err FCS-Err Xmit-Err Rcv-Err UnderSize OutDiscards ',
'Gi0/1 0 0 0 0 0 212086 ',
'Gi0/2 0 0 0 0 0 184832 ',
'Gi0/3 0 0 23 0 0 315887 ',
'Gi0/4 0 0 0 0 0 253439 ',
'Gi0/5 0 0 0 0 0 135034 ',
'Gi0/6 0 0 0 0 0 132617 ',
'Gi0/7 0 0 0 0 0 5816 ',
'Gi0/8 0 0 0 0 0 12266 ',
'Gi0/9 0 0 0 0 0 573217 ',
'Gi0/10 0 0 0 0 0 844880 ',
'Gi0/11 0 0 0 0 0 264766 ',
'Gi0/12 0 0 0 0 0 197496 ',
'Gi0/13 0 0 0 0 0 0 ',
'Gi0/14 0 0 0 0 0 372725 ',
'Gi0/15 0 0 0 0 0 14260434 ',
'Gi0/16 0 116 0 116 0 56 ',
'Gi0/17 0 0 0 0 0 6905901 ',
'Gi0/18 0 0 0 0 0 333387 ',
'Po1 0 232464 0 232464 0 21331230 ',
]
# Splits at space
for row in array:
rowData = row.split()
if(rowData[2] != '0'):
print(row)
产生
Port Align-Err FCS-Err Xmit-Err Rcv-Err UnderSize OutDiscards
Gi0/16 0 116 0 116 0 56
Po1 0 232464 0 232464 0 21331230
答案 2 :(得分：1)
请修改您的问题，不清楚。
我假设您希望一个或多个'something-Err'列的值不为零
您可以执行以下操作：
def f(arr):
yield arr[0] # labels
for elem in arr[1:]:
_, align_err, fcs_err, xmit_err, rcv_err, *_ = elem.split()
if any(map(lambda s: int(s) != 0, (align_err, fcs_err, xmit_err, rcv_err))):
yield elem
然后像这样使用它：
>>> for elem in f(array):
... print(elem)
...
Port Align-Err FCS-Err Xmit-Err Rcv-Err UnderSize OutDiscards
Gi0/3 0 0 23 0 0 315887
Gi0/16 0 116 0 116 0 56
Po1 0 232464 0 232464 0 21331230
答案 3 :(得分：1)
for i in array:
if any(x!="0" for x in i.split()[1:-1]): # here 1:-1 are the range where we are checking the values, you can edit it as per your need
print (i)
print ([i for i in array if any(x!="0" for x in i.split()[1:-1])])
Port Align-Err FCS-Err Xmit-Err Rcv-Err UnderSize OutDiscards
Gi0/3 0 0 23 0 0 315887
Gi0/16 0 116 0 116 0 56
Po1 0 232464 0 232464 0 21331230
def getErrorList(array):
return [i for i in array if any(x!="0" for x in i.split()[1:-2])] #check the range [1:-2] carefully. Use it as per your need.
print (getErrorList(array)) #take it in a variable for further processing