Question

例如我有这个数组

    var array1 = [{ uid=24433357, first_name="fname", last_name="lname", ...},
{ uid=4821888, first_name="fname", last_name="lname", ...},
{ uid=677614, first_name="fname", last_name="lname", ...},
{ uid=4789723, first_name="fname", last_name="lname", ...},
{ uid=444464, first_name="fname", last_name="lname", ...},
{ uid=767687867, first_name="fname", last_name="lname", ...}]

我想从array1中删除元素，其中uid = x

我不知道怎么做？

对于普通数组我知道这个方法

array1.splice(index, count)

Answer 1

首先修复你的对象，语法都错了。请参阅下文，然后使用Array＃filter函数按uid

过滤掉不需要的对象

var array1 = [{ uid:24433357, first_name:"fname", last_name:"lname"},
    { uid:4821888, first_name:"fname", last_name:"lname"},
    { uid:677614, first_name:"fname", last_name:"lname"},
    { uid:4789723, first_name:"fname", last_name:"lname"},
    { uid:444464, first_name:"fname", last_name:"lname"},
    { uid:767687867, first_name:"fname", last_name:"lname"}];

ES5 不适合旧浏览器

array1 = array1.filter(function(o){
    return o.uid !== 24433357
});

经典方式与旧浏览器兼容

for (var i = 0; i < array1.length; i++) {

    if (array1[i].uid === 24433357) {
        array1.splice(i, 1);
    }
}

console.log(array1);

Answer 2

for(var i = array1.length-1; i--;){
    if (array1.uid[i] === "x") array1.splice(i, 1);
}

从元素相等的数组中删除元素

2 个答案: