Question

我有下一个PHP代码，该代码使我成为一个包含SQL表中数据的JSON文件：

<?php
$mysqli = new mysqli('localhost','root','xxxx','xxxx');
$myArray = array();
$result = $mysqli->query("SELECT CONCAT(Datum , ' ', Tijd) as Datum, KleurL FROM metingen order by Datum ASC limit 20");
if ($result) {
  $tempArray = array();
  while ($row = $result->fetch_object()) {
    $tempArray = $row;
    array_push($myArray, $tempArray);
  }
  echo json_encode($myArray,JSON_NUMERIC_CHECK);
  $fp = fopen('resultsv2.json', 'w');
  fwrite($fp, json_encode($myArray,JSON_NUMERIC_CHECK));
  fclose($fp);
}
$result->close();
$mysqli->close();
?>

JSON文件的输出如下所示：

[{"Datum":"17-01-2019 10:31:39","KleurL":17.68},{"Datum":"17-01-2019 11:10:59","KleurL":71.76},{"Datum":"18-01-2019 08:40:41","KleurL":70.7},{"Datum":"18-01-2019 10:30:01","KleurL":71.03},{"Datum":"18-01-2019 12:05:46","KleurL":70.56},{"Datum":"18-01-2019 14:31:58","KleurL":16.2}]

但是我想看到该文件的输出看起来像这样。

[
  [
    17.68,
    17-01-2019 10:31:39
  ],
  [
    18.11,
    17-01-2019 11:15:20
  ]
]

如何在JSON文件中获取此输出？

Answer 1

下面的代码应该可以实现您想要的目的。该代码已在我的PC上进行了测试，似乎运行良好。

<?php $mysqli = new mysqli('localhost', 'root', 'xxxx', 'xxxx');
if ($result = $mysqli->query("SELECT CONCAT(Datum , ' ', Tijd) as Datum, KleurL FROM metingen order by Datum ASC limit 20")) {
    $current_row_number = 0;

    $output = "[";
    while ($row = $result->fetch_object()) {
        if ($current_row_number > 0) {
            $output = $output . ","; //add comma between each row
        }

        $output = $output . "[" . $row->KleurL . "," . $row->Datum . "]"; //add each row

        $current_row_number++;
    }
    $output = $output . "]";

    echo $output;

    $fp = fopen('resultsv2.json', 'w');
    fwrite($fp, $output);
    fclose($fp);
}

$result->close();
$mysqli->close();

如果要很好地格式化输出，请使用以下代码：

<?php $mysqli = new mysqli('localhost', 'root', '244466666', 'tkd');
if ($result = $mysqli->query("SELECT CONCAT(Datum , ' ', Tijd) as Datum, KleurL FROM metingen order by Datum ASC limit 20")) {
    $current_row_number = 0;

    $output = "[";
    while ($row = $result->fetch_object()) {
        if ($current_row_number > 0) {
            $output = $output . ","; //add comma between each row
        }

        $output = $output . "\n\t" . "[" . "\n\t\t" . $row->KleurL . "," . "\n\t\t" . $row->Datum . "\n\t" . "]"; //add each row

        $current_row_number++;
    }
    $output = $output . "\n]";

    // echo $output; //if you want to see the output in the terminal/command prompt
    echo "<pre>" . $output . "</pre>"; //if you want to see the output in a browser

    $fp = fopen('resultsv2.json', 'w');
    fwrite($fp, $output);
    fclose($fp);
}

$result->close();
$mysqli->close();

Answer 2

您可以使用json_encode() JSON_PRETTY_PRINT选项：

json_encode($myArray,JSON_NUMERIC_CHECK | JSON_PRETTY_PRINT);

编辑：

如果您使用的是Windows，则需要使用以下方式更改回车符：

$myArray = array("test" => "data");

$buffer = json_encode($myArray,JSON_NUMERIC_CHECK | JSON_PRETTY_PRINT);

echo str_replace("\n", "\r\n", $buffer);
// or
$fp = fopen('resultsv2.json', 'w');
fwrite($fp, str_replace("\n", "\r\n", $buffer));
fclose($fp);

如果将其打印到浏览器中，则需要使用<pre>标签

<pre>
echo json_encode($myArray,JSON_NUMERIC_CHECK | JSON_PRETTY_PRINT);
</pre>

更改文件中的格式JSON输出？

2 个答案: