Question

我正在研究一种以json格式提供输出的情感api 现在我想在php中解析它

{ "status": "OK", "usage": "By accessing AlchemyAPI or using information generated by AlchemyAPI, you are agreeing to be bound by the AlchemyAPI Terms of Use: http://www.alchemyapi.com/company/terms.html", "url": "", "language": "english", "docSentiment": { "type": "neutral" } }

这是我输出的json格式。

我想要输出"type" = "neutral"

Answer 1

您可以使用json_decode()将其解码为PHP对象或数组。

下面我添加了使用2中的任何一个的示例。

$json = '{
    "status": "OK",
    "usage": "By accessing AlchemyAPI or using information generated by AlchemyAPI, you are agreeing to be bound by the AlchemyAPI Terms of Use: http://www.alchemyapi.com/company/terms.html",
    "url": "",
    "language": "english",
    "docSentiment": {
        "type": "neutral"
    }
}';

// Convert to associative array  
// (remove the second parameter to make it an object instead)
$array = json_decode($json, true);
$object = json_decode($json);

// Output the docSentiment type
echo $array['docSentiment']['type']; // Output: 'neutral'
echo $object->docSentiment->type; // Output: 'neutral'

Answer 2

您可以使用json_decode然后转到相关内容：

 $json=<<<JSON
{ "status": "OK", "usage": "By accessing AlchemyAPI or using information generated by AlchemyAPI, you are agreeing to be bound by the AlchemyAPI Terms of Use: http://www.alchemyapi.com/company/terms.html", "url": "", "language": "english", "docSentiment": { "type": "neutral" } }
JSON;
$json = json_decode($json);
echo $json->docSentiment->type;

输出：neutral

Answer 3

尝试reading the manual如何解码json。

这将为您提供PHP版本的数据：

$strJson = '{ "docSentiment": { "type": "neutral" } }';
$data = json_decode($strJson);
var_dump($data);

这个答案很容易在谷歌上找到......

Answer 4

使用json_decode，这是解码数据的PHP版本

解析php文件中的json格式输出

4 个答案: