Question

我有一个名为Activite的实体引用自己，（一个Activite可以有很多活动），我试图通过休息服务获得所有活动。这是实体：

@Entity
public class Activite implements Serializable{
@Id @GeneratedValue(strategy = GenerationType.IDENTITY)
private long id_act;

private String designation_fr;
private String designation_ar;
private String libelle;

@ManyToOne
private Activite parent;
@OneToMany(mappedBy="parent")
private Collection<Activite> children;

public Collection<Activite> getChildren() {
    return children;
}
public void setChildren(Collection<Activite> children) {
    this.children = children;
}
@JsonIgnore
public Activite getParent() {
    return parent;
}
public void setParent(Activite parent) {
    this.parent = parent;
}

这是我得到的Json格式：

[{
"id_act": 1,
"designation_fr": "fr",
"designation_ar": "cfd",
"libelle": "Activite 1",
"children": [
{
 "id_act": 11,
 "designation_fr": "bhjf",
 "designation_ar": "dhbf",
 "libelle": "Activite 1.1",
 "children": [],
 "id_prj": 1
 },
 {
 "id_act": 12,
 "designation_fr": "njkj",
 "designation_ar": "ffrgrn",
 "libelle": "Activite 1.2",
 "children": [],
 "id_prj": 1
 },
 {
 "id_act": 13,
 "designation_fr": "njkdj",
 "designation_ar": "frjn",
 "libelle": "Activite 1.3",
 "children": [
 {
 "id_act": 131,
 "designation_fr": "hcchchc",
 "designation_ar": "GFVVHG",
 "libelle": "Activite 1.3.1",
 "children": [],
 "id_prj": 1
 }
 ],
 "id_prj": 1
 }
 ],
 "id_prj": 1
 },
 {
 "id_act": 11,
 "designation_fr": "bhjf",
 "designation_ar": "dhbf",
 "libelle": "Activite 1.1",
 "children": [],
 "id_prj": 1
 },
 {
 "id_act": 12,
 "designation_fr": "njkj",
 "designation_ar": "ffrgrn",
 "libelle": "Activite 1.2",
 "children": [],
 "id_prj": 1
 },
 {
 "id_act": 13,
 "designation_fr": "njkdj",
 "designation_ar": "frjn",
 "libelle": "Activite 1.3",
 "children": [
 {
 "id_act": 131,
 "designation_fr": "hcchchc",
 "designation_ar": "GFVVHG",
 "libelle": "Activite 1.3.1",
 "children": [],
 "id_prj": 1
 }
 ],
 "id_prj": 1
 },
 {
 "id_act": 131,
 "designation_fr": "hcchchc",
 "designation_ar": "GFVVHG",
 "libelle": "Activite 1.3.1",
 "children": [],
 "id_prj": 1
 }
 ]

这就是我想要的：

[
      {
            "id_act": 1,
            "designation_fr": "fr",
            "designation_ar": "cfd",
            "libelle": "Activite 1",
            "children": [
              {
                "id_act": 11,
                "designation_fr": "bhjf",
                "designation_ar": "dhbf",
                "libelle": "Activite 1.1",
                "children": [],
                "id_prj": 1
              },
              {
                "id_act": 12,
                "designation_fr": "njkj",
                "designation_ar": "ffrgrn",
                "libelle": "Activite 1.2",
                "children": [],
                "id_prj": 1
              },
              {
                "id_act": 13,
                "designation_fr": "njkdj",
                "designation_ar": "frjn",
                "libelle": "Activite 1.3",
                "children": [{
                    "id_act": 131,
                    "designation_fr": "njkdj",
                    "designation_ar": "frjn",
                    "libelle": "Activite 1.3.1",
                    "children": [],
                    "id_prj": 1
                  }],
                "id_prj": 1
              }
            ],
            "id_prj": 1
          }]

如你所见，Activite的id为11 12 13和131是重复的，我希望它们只在children数组中我实际上是在angularjs中调用其余服务，所以是否可以更改我在angularjs中获得的json格式，或者我应该在后端更改查询

Answer 1

我希望您已粘贴上面的响应json 。最好更改后端代码以获得所需的正确json，这样您就可以使用json进行进一步处理。

如何更改Json格式输出

1 个答案: