即使我在CSS中设置了[transform-origin:100%50%;],但与X轴和Y轴相比,该表单也不会围绕其中心旋转。
问题:如何使表格旋转准确地从其中点开始计数。
.box {
background-color: pink;
margin: 300px 0 0 300px;
width: 200px;
height: 200px;
}
.box {
position: absolute;
animation: spin 10s;
animation-fill-mode: forwards;
}
.line-horizontal {
background-color: black;
width: 200px;
height: 5px;
margin: 100px 0 0 0;
}
.line-vertical {
background-color: black;
width: 5px;
height: 200px;
margin: -105px 0 0 100px;
}
@keyframes spin {
from {
transform:rotate(0deg);
transform-origin: 100% 50%;
}
to {
transform:rotate(360deg);
}
}
<div class="box">
<div class="line-horizontal"></div>
<div class="line-vertical"></div>
</div>
答案 0 :(得分:0)
将tranform-origin
更改为50% 50%
,这意味着两个轴的中心都不要放在关键帧内,因为它会变得生动
.box {
background-color: pink;
width: 200px;
height: 200px;
}
.box {
position: absolute;
animation: spin 10s;
animation-fill-mode: forwards;
transform-origin: 50% 50%;
/*center*/
}
.line-horizontal {
background-color: black;
width: 200px;
height: 5px;
margin: 100px 0 0 0;
}
.line-vertical {
background-color: black;
width: 5px;
height: 200px;
margin: -105px 0 0 100px;
}
@keyframes spin {
from {
transform: rotate(0deg);
}
to {
transform: rotate(360deg);
}
}
<div class="box">
<div class="line-horizontal"></div>
<div class="line-vertical"></div>
</div>
如果您需要相同的外观,也可以像下面那样简化代码:
.box {
width: 200px;
height: 200px;
background:
linear-gradient(#000,#000) center/100% 5px,
linear-gradient(#000,#000) center/5px 100%,
pink;
background-repeat:no-repeat;
animation: spin 10s forwards;
transform-origin: 50% 50%; /* OR center*/
}
@keyframes spin {
from {
transform: rotate(0deg);
}
to {
transform: rotate(360deg);
}
}
<div class="box">
</div>