使用oscP5处理蚱grass

时间:2018-12-30 17:54:48

标签: java processing osc oscp5

我试图查看是否可以使用oscP5将在处理中生成的草图链接到蚱grass。草图是此编码培训视频的上半部分概述的点范围:

https://www.youtube.com/watch?v=RkuBWEkBrZA

在我开始将其与oscP5链接之前的代码似乎运行良好:

import peasy.*;

PeasyCam cam;

PVector[][] globe;
int total = 20;

void setup() {
  size(600, 600, P3D);
  cam = new PeasyCam(this, 500);

  globe = new PVector[total+1][total+1];
}

void draw() {
  background(0);
  fill(255);
  lights();

  float r = 200;

  for (int i = 0; i < total+1; i++) {
    float lat = map(i, 0, total, 0, PI);
    for (int j = 0; j < total+1; j++) {
      float lon = map(j, 0, total, 0, TWO_PI);
      float x = r * sin(lat) * cos(lon);
      float y = r * sin(lat) * sin(lon);
      float z = r * cos(lat);   
      globe[i][j] = new PVector(x, y, z);        
    }
  }
  noFill();   
  for (int i = 0; i < total; i++) {
    beginShape(TRIANGLE_STRIP); 
    for (int j = 0; j < total+1; j++) {
      PVector v1 = globe[i][j];
      stroke(255);
      strokeWeight(2);
      vertex(v1.x, v1.y, v1.z);   

      PVector v2 = globe[i+1][j];
      vertex(v2.x, v2.y, v2.z); 
    }
    endShape();
  }
}

但是,当我尝试实现oscP5时,效果并不理想。我的蚱file文件接收到了正确的分数,但是要点并不正确,因此我必须与发送的数据有关的问题,但是我似乎无法弄清楚应该发送的数据。该代码采用指定的半径,经度和纬度的值,并将其转换为x,y,z坐标,而我试图让oscP5发送这些x,y,z坐标。

有人有什么想法吗?到目前为止的代码如下。

//import necessary libraries
import oscP5.*;
import netP5.*;

OscP5 oscP5;
NetAddress myRemoteLocation;

//import camera
import peasy.*;

PeasyCam cam;

// message to send
String message;

PVector[][] sphere;
int total = 20;

float lat;
float lon;

void setup() {
  size(600, 600, P3D);
  cam = new PeasyCam(this, 500);

  sphere = new PVector[total+1][total+1];

//send message from this port
  oscP5 = new OscP5(this,12000);      
//send message to this port
  myRemoteLocation = new NetAddress("127.0.0.1",12001);
}

void draw() {
  background(0);
  fill(255);
  lights();

  float r = 200;

  for (int i = 0; i < total+1; i++) {
    float lat = map(i, 0, total, 0, PI);
    for (int j = 0; j < total+1; j++) {
      float lon = map(j, 0, total, 0, TWO_PI);
      float x = r * sin(lat) * cos(lon);
      float y = r * sin(lat) * sin(lon);
      float z = r * cos(lat);   
      sphere[i][j] = new PVector(x, y, z);        
    }
  }
  noFill();    
  for (int i = 0; i < total; i++) {
    beginShape(TRIANGLE_STRIP); 
    for (int j = 0; j < total+1; j++) {
      PVector v1 = sphere[i][j];
      stroke(255);
      strokeWeight(2);
      vertex(v1.x, v1.y, v1.z);   

      PVector v2 = sphere[i+1][j];
      vertex(v2.x, v2.y, v2.z); 
    }
    endShape();
  }

// osc message
  OscMessage myMessage = new OscMessage("/hello world");


for (int j = 0; j < total+1; j++) {
//message to send 
message  = "x = " + String.valueOf(r * sin(lat) * cos(lon)) + "; " + 
           "y = " + String.valueOf(r * sin(lat) * sin(lon))+ "; " +
           "z = " + String.valueOf(r * cos(lat))+ "; " ;

    myMessage.add(String.valueOf(r * sin(lat) * cos(lon)));
    myMessage.add(String.valueOf(r * sin(lat) * sin(lon))); 
    myMessage.add(String.valueOf(r * cos(lat))); 
  }

//print message
  println(message);
//send message
  oscP5.send(myMessage, myRemoteLocation);
}

我认为错误在于代码的这一部分

for (int j = 0; j < total+1; j++) {
//message to send 
message  = "x = " + String.valueOf(r * sin(lat) * cos(lon)) + "; " + 
           "y = " + String.valueOf(r * sin(lat) * sin(lon))+ "; " +
           "z = " + String.valueOf(r * cos(lat))+ "; " ;

    myMessage.add(String.valueOf(r * sin(lat) * cos(lon)));
    myMessage.add(String.valueOf(r * sin(lat) * sin(lon))); 
    myMessage.add(String.valueOf(r * cos(lat))); 
  }

任何帮助都会很棒。

1 个答案:

答案 0 :(得分:2)

永远不要设置float lat;全局变量的值,因为在嵌套的float lon;循环中,声明了两个新的局部变量(在循环块作用域中):

for

请注意,for (int i = 0; i < total+1; i++) { float lat = map(i, 0, total, 0, PI); for (int j = 0; j < total+1; j++) { float lon = map(j, 0, total, 0, TWO_PI); // [...] } } 声明了一个新变量,float lat = ...是对现有变量lat = ...的赋值。

但是使用全局变量而不是设置新变量不会改变任何内容,因为在发送消息时,变量latlat将具有最后一次迭代的值。嵌套循环。

您必须实现2个新循环,并且必须重新计算lonlat的值。循环后的print语句没有任何意义,因为它将仅打印最后一个坐标。

代码应如下所示:

lon