Question

您好，我正在制作一个游戏，并且正在尝试对其进行编程，因此用户正在考虑一个随机数，并且程序会尝试对其进行猜测。我必须使用消息对话框（这是一个学校项目），它询问用户该数字是否太高，太低或正确，但是当数字太低时，它将猜测更高的数字。有什么问题（假设计数已初始化为0。）

boolean correctGuess = false; // when computer guesses incorrectly, correctGuess is false

String n = JOptionPane.showInputDialog("Is " + progNum + " too high, too low, or correct?", " ");


while(correctGuess == false)   // when the computer is guessing
{

if(n.equals("correct"))  // if the number is correct 
{
  count++;     // update number of guesses
  JOptionPane.showMessageDialog(null, "Yay! " + progNum + " was correct! It took the computer " + count + " guesses."); // correct guess, displays number of guesses
  correctGuess= true;  // computer guessed the correct number
  break;  // program stops
}
else if(n.equals("too high")) // number is too high, prog generates lower number
{
  count++;      // update number of guesses
  int max = (progNum - 1);        // guess was too high so progNum-1 is the max
  int min = 1;        // min value is progNum + 1 since progNum is too high
  progNum = generator.nextInt((max - min) + 1) + min;      // new range for progNum between 1 and progNum1 - 1
  String tooHigh = JOptionPane.showInputDialog("Is " + progNum + " too high, too low, or correct?", " "); // asks user

  if (tooHigh == null)
   return;

 }
else if(n.equals("too low")) // number is too low, prog generates higher number
{
  count++;          // update number of guesses
  int max = 100;     // generate a range of values for another random guess
  int min = (progNum + 1);      // min value is progNum + 1 since progNum is too low
  progNum = generator.nextInt((max - min) + 1) + min;      // new range for progNum between 1 and progNum1 + 1
  String tooLow = JOptionPane.showInputDialog("Is " + progNum + " too high, too low, or correct?", " ");  // asks user

  if (tooLow == null)
   return;
}

Answer 1

问题是您从不更新n。插入while循环，当您询问它是否太高或太低时，会将用户的答案存储在另一个变量中。您需要像开始时那样将用户答案存储在n中。

Answer 2

进行一些更改可能会使此操作更容易理解。我认为，基本问题是循环中要检查“ n”，但是要在if语句中重新收集结果。

您可以将计数增加从单个if语句中移出，并允许在循环内收集响应。

int min = 0;
int max = 100;

// loop while an incorrect guess
while (! correctGuess) {
  // do a binary search
  //  max and min are updated on each check
  int progNum = ((max - min) / 2) + min;

  // collect the response
  String n = JOptionPane.showInputDialog("Is " + progNum + " too high, too low, or correct?", " ");

  // cancel by user
  if (n == null) {
    break;
  }      

  // user made a guess
  ++count;

  if (n.equals("correct")) {
    OptionPane.showMessageDialog(null, "Yay! " + progNum + " was correct! It took the computer " + count + " guesses."); // correct guess, displays number of guesses
    correctGuess= true;  // computer guessed the correct number
    continue;  // program stops
  }
  else if (n.equals("too high")) {
    max = progNum - 1;
  }
  else if (n.equals("too low")) {
    min = progNum + 1;
  }
}

编辑：您可能希望仔细查看下一个猜测数字的生成方式。我认为纯二进制搜索方法比选择一个范围内的随机数更有效。

编辑2：您可以看到基本的二进制搜索方法at this link here。

计算机猜谜游戏中的消息对话框

2 个答案: