Question

我有一个这样的数据框：

zip      season   season_start_date   season_end_date
zip1     winter   2015-11-25          2016-03-09

我需要一种将开始日期和结束日期之间的日期展平的方法。我希望这样的输出：

zip       season   date   
zip1      winter   2015-11-25
zip1      winter   2015-11-26
.
.
zip1      winter   2016-03-09

我怎么能更优雅地实现？

data = {"zip":["zip1","zip1"],
    "season":["s6","s6"],
    "season_start_date": ["2011-01-01","2011-01-01"], 
    "season_end_date" : ["2012-01-05","2012-01-05"]
   }
df = pd.DataFrame(data=data)

谢谢。

Answer 1

from datetime import datetime, timedelta

Row_to_split = df.loc[1]
Season = Row_to_split['season']
Start_Date = datetime.strptime(Row_to_split['season_start_date']', '%Y-%m-%d')
End_Date = datetime.strptime(Row_to_split['season_end_date']', '%Y-%m-%d')
# initialize new_df 
for i in range((End_Date - Start_Date).days+1):
    new_df.loc[i] = [season, (Start_Date+timedelta(i)).strftime('%Y-%m-%d')]

那是您想要的吗？我不确定zip列是否为索引，但是如何插入它应该很明显。

Answer 2

您将需要从每一行生成一个DataFrame，然后将它们连接在一起：

julia> Vector{Float64}.(JSON.parse(trip))
3-element Array{Array{Float64,1},1}:
 [-8.7, 6.4]
 [7.4, 9.7]
 [3.4, 2.1]

通过展平两列来创建python数据框

2 个答案: