如何在Pygame中绘制透明矩形

时间:2018-11-11 07:21:11

标签: pygame width transparent rect outline

我可以画一个内部透明但矩形不透明的矩形吗?如果可以设置轮廓的宽度会更好。

like this

1 个答案:

答案 0 :(得分:2)

如果只想绘制矩形的轮廓,则可以将整数作为第四个(width)参数传递给pygame.draw.rect

pygame.draw.rect(screen, (0, 100, 255), (50, 50, 162, 100), 3)  # width = 3

这种方法的问题在于,拐角看起来不清晰,轮廓不透明。


您还可以使用gfxdraw模块通过for循环绘制多个轮廓:

def draw_rect_outline(surface, rect, color, width=1):
    x, y, w, h = rect
    width = max(width, 1)  # Draw at least one rect.
    width = min(min(width, w//2), h//2)  # Don't overdraw.

    # This draws several smaller outlines inside the first outline. Invert
    # the direction if it should grow outwards.
    for i in range(width):
        pygame.gfxdraw.rectangle(screen, (x+i, y+i, w-i*2, h-i*2), color)

draw_rect_outline(screen, (250, 50, 162, 100), (0, 100, 255, 155), 9)

这还允许您通过alpha通道传递颜色以使轮廓透明。


还可以创建一个透明表面并在其上绘制一个矩形(也可以在此处传递透明颜色):

surf = pygame.Surface((162, 100), pygame.SRCALPHA)
pygame.draw.rect(surf, (0, 100, 255, 155), (0, 0, 162, 100), 21)

如果您想要一个填充的透明矩形,只需fill整个表面:

surf.fill((0, 100, 255, 155))