Question

我正在尝试使用带有树莓派的ps4控制器来生成输入。我已经成功连接了控制器，当我尝试运行以下在pygame网站上找到的代码时，一切运行正常。

import pygame


BLACK    = (   0,   0,   0)
WHITE    = ( 255, 255, 255)


class TextPrint:
    def __init__(self):
        self.reset()
        self.font = pygame.font.Font(None, 20)

    def print(self, screen, textString):
        textBitmap = self.font.render(textString, True, BLACK)
        screen.blit(textBitmap, [self.x, self.y])
        self.y += self.line_height

    def reset(self):
        self.x = 10
        self.y = 10
        self.line_height = 15

    def indent(self):
        self.x += 10

    def unindent(self):
        self.x -= 10


pygame.init() 
size = [500, 700]
screen = pygame.display.set_mode(size)
pygame.display.set_caption("My Game")


done = False

clock = pygame.time.Clock()


pygame.joystick.init()


textPrint = TextPrint()


while done==False:

    for event in pygame.event.get(): # User did something
        if event.type == pygame.QUIT: # If user clicked close
            done=True # Flag that we are done so we exit this loop

       JOYBUTTONUP JOYHATMOTION
        if event.type == pygame.JOYBUTTONDOWN:
            print("Joystick button pressed.")
        if event.type == pygame.JOYBUTTONUP:
            print("Joystick button released.")



    screen.fill(WHITE)
    textPrint.reset()

    joystick_count = pygame.joystick.get_count()

    textPrint.print(screen, "Number of joysticks: {}".format(joystick_count) )
    textPrint.indent()


    for i in range(joystick_count):
        joystick = pygame.joystick.Joystick(i)
        joystick.init()

        textPrint.print(screen, "Joystick {}".format(i) )
        textPrint.indent()

        name = joystick.get_name()
        textPrint.print(screen, "Joystick name: {}".format(name) )

        axes = joystick.get_numaxes()
        textPrint.print(screen, "Number of axes: {}".format(axes) )
        textPrint.indent()

        for i in range( axes ):
            axis = joystick.get_axis( i )
            textPrint.print(screen, "Axis {} value: {:>6.3f}".format(i, axis) )
        textPrint.unindent()

        buttons = joystick.get_numbuttons()
        textPrint.print(screen, "Number of buttons: {}".format(buttons) )
        textPrint.indent()

        for i in range( buttons ):
            button = joystick.get_button( i )
            textPrint.print(screen, "Button {:>2} value: {}".format(i,button) )
        textPrint.unindent()


        hats = joystick.get_numhats()
        textPrint.print(screen, "Number of hats: {}".format(hats) )
        textPrint.indent()

        for i in range( hats ):
            hat = joystick.get_hat( i )
            textPrint.print(screen, "Hat {} value: {}".format(i, str(hat)) )
        textPrint.unindent()

        textPrint.unindent()



    pygame.display.flip()


    clock.tick(20)

pygame.quit ()

是的，当我运行上面的代码时，一切正常，但是我根本不想生成游戏，我只想从d键盘或帽子获得输入。为此，我根据上面的代码编写了自己的代码

 import pygame
    pygame.joystick.init()
    while True:
        joystick = pygame.joystick.Joystick(0)
        joystick.init()
        hat = joystick.get_hat(0)
        print(str(hat))

当我运行上面的代码时，它将运行并且没有语法错误，但是无论我按下了d-pad的哪个按钮，它都会连续打印（0,0）。控制器仍处于连接状态，这提示我由于某种原因我的新代码无法接收输入。

感谢您抽出宝贵的时间阅读这篇长文章，任何帮助将不胜感激。

亲切的问候

Answer 1

您必须定期调用pygame.event函数之一（例如pygame.event.pump或for event in pygame.event.get():），否则将不会调用Joystick.get_hat和pygame.mouse.get_pressed之类的函数工作，一段时间后pygame窗口将无响应。

您也不需要在每一帧都创建和初始化一个新的操纵杆对象。在while循环之前执行一次。这是一个最小的完整示例：

import pygame as pg


pg.init()
screen = pg.display.set_mode((100, 100))
clock = pg.time.Clock()

# Create a list of available joysticks and initialize them.
joysticks = [pg.joystick.Joystick(x) for x in range(pg.joystick.get_count())]
for joystick in joysticks:
    joystick.init()

running = True
while running:
    for event in pg.event.get():
        if event.type == pg.QUIT:
            running = False
        elif event.type == pg.JOYBUTTONDOWN:
            if event.button == 6:  # Back button.
                running = False

    for joystick in joysticks:  # Iterate over the available joysticks.
        if joystick.get_id() == 0:  # The first joystick.
            numhats = joystick.get_numhats()
            for hat in range(numhats):  # Check all hats of the joystick.
                print(joystick.get_hat(hat))

    screen.fill((30, 30, 50))
    pg.display.flip()
    clock.tick(60)

pg.quit()

编辑的操纵杆代码未接收到输入

1 个答案: