我想将熊猫中的列分组

Question

我有包含不同列的数据框，并且我想以AccountID为基础对列进行分组  

和预期的输出看起来像这样

Answer 1

尝试一下：

uniq_accounts = differenc['AccountID'].unique()
grped = differenc.groupby('AccountID')

## You can get the grouped data for a certain AccountId like this and store in a dictionary:

d = {}
for account in uniq_accounts:
    d[account] = grped.get_group(account)

##Now, dictionary has all accounts data in separate dataframes. You can access like this:

for key in d.keys():
    print(d[key])

## If you want to fetch data for a particular AccountID(lets say 316001718201), you can do:

print(d['316001718201'])

让我知道是否有帮助。

Answer 2

使用DataFrame的groupby函数应该可以实现，在这种情况下，该函数可能为differenc.groupby('AccountID')